A key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P) as shown below. G6P ---> F6P At 298 K, the equilibrium constant for the isomerization is 0.510. (a) Calculate G° at 298 K._______.  kJ/mol(b) Calculate G when Q, the [F6P]/[G6P] ratio, equals 21.0._______ kJ/mol(c) Calculate G when Q = 0.800._______ kJ/mol(d) Calculate Q in the cell if G = -2.90 kJ/mol.

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter17: Chemcial Thermodynamics
Section: Chapter Questions
Problem 17.90QE: For each reaction, an equilibrium constant at 298 K is given. Calculate G for each reaction. (a)...
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A key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P) as shown below.

G6P ---> F6P

At 298 K, the equilibrium constant for the isomerization is 0.510.

(a) Calculate G° at 298 K.
_______.  kJ/mol
(b) Calculate G when Q, the [F6P]/[G6P] ratio, equals 21.0.
_______ kJ/mol
(c) Calculate G when Q = 0.800.
_______ kJ/mol
(d) Calculate Q in the cell if G = -2.90 kJ/mol.
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