Question
Asked Dec 9, 2019
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A large cruise ship of mass 6.70 ✕ 107 kg has a speed of 12.4 m/s at some instant.

What is the magnitude of the constant force required to stop it as it undergoes a displacement of 2.90 km?

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Expert Answer

Step 1

According to the work kinetic energy theorem, the work done on an object is equal to the change in kinetic energy of the object.

Substitute the values,

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W = AK = K; – K, =m(r* -u° ) w =(6.70x10' kg) (0*)-(12.4m/s)*| =-5.2×10° J

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Step 2

The force exerted on the ship to stop it,

Substitute the values,

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W = Fd F = -5.2x10° J F= 10°m 2.90km 1km -5.2x10° J 2.90x 10° m =-1.79×10° N

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Step 3

Hence, negative value indicates that the force is opposite to the displacement of the...

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|F|=1.79×10° N z1.8×10°N

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