Asked Dec 4, 2019

A lawn mower (25 kg) is pushed downard with a force of 50 Newton's at an angle of 60 degrees with the horizontal. 

a. What is the normal force?

b. If the frictional force opposing the motion is 20 Newton's, then what is the lawn mower's acceleration?


Expert Answer

Step 1


The required normal...


Image Transcriptionclose

N=mg Fsin@ -[(25)(98)+[(50)sin(s0)] =288.3 N


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