A length of aluminum wire has a resistance of 30.0 Ωat 20.0°C. When the wire is warmed in an oven and reaches thermal equilibrium, the resistance of the wire increases to46.2 Ω. (a) Neglecting thermal expansion, find the temperatureof the oven. (b) Qualitatively, how would thermal expansionbe expected to affect the answer?

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Asked Dec 19, 2019
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A length of aluminum wire has a resistance of 30.0 Ω
at 20.0°C. When the wire is warmed in an oven and reaches thermal equilibrium, the resistance of the wire increases to
46.2 Ω. (a) Neglecting thermal expansion, find the temperature
of the oven. (b) Qualitatively, how would thermal expansion
be expected to affect the answer?

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Given Info: The resistance of aluminum wire at 20.0 °C is 30.0 2. On warming, the resistance increases to 46.2 N. Formula to calculate the temperature is (R/Ro)–1 T=To + Ris the resistance at some temperature T, • Ro is the resistance at some reference temperature To, • a is the temperature coefficient of resistivity of silver, Substitute 30.0 N for Ro,46.2 N for R,20.0 °C for Tô, and for a to find T. 3.9 x 10 3(°C) (46.2 2/30.0 12)– 1 3.9x10 ("C)- T = 20.0 °C + %3D 158.46°C %3D 1.6 x 102°C

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Conclusion: Therefore, the final temperature of oven is 1.6 x 102°C

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