Asked Oct 22, 2019

A Li2+ ion emitts a photon with a frequency of 6.66 × 1014 Hz. If the energy of the initial state of the Li2+ ion was -7.85 × 10(-19) J, calculate the energy of the final state. Express answer in scientific notation.

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Step 1

Energy difference between two states is determined...

AE hv
(6.626x 1034 Js) (6.66 x 104 Hz)
4.41x1019 J

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AE hv (6.626x 1034 Js) (6.66 x 104 Hz) 4.41x1019 J


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