Question
Asked Dec 8, 2019
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A light spring with spring constant 1100 N/m hangs from an elevated support. From its lower end hangs a second light spring, which has spring constant 1950 N/m. An object of mass 1.50 kg is hung at rest from the lower end of the second spring.

(a) Find the total extension distance of the pair of springs
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Given Spaing constant of Sirst spring, k, = l100 N/m Spring Constant of second Spaing , K2= 1950 Mm Object mass, Accelesation due to grevily, 9= 9.81 M/sz m= 1.50 kg

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elevated Support Kz mg

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Step 3
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Spring connected în series so equivalent Spping Constant is to knet kikz Kitkz knet (1100 N/m) (1950N(m) (1100 N/m + 1950 N/m) 703.27 N/m

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