Question
Asked Oct 26, 2019
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A man sits with his back against the back of a chair, and he pushes a block of mass m = 6 kg straight forward on a table in front of him, with a constant force F = 26 N, moving the block a distance d = 0.8 m. The block starts from rest and slides on a low-friction surface.

What is the change in internal energy of the man? In Joules

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Step 1

Given,

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F 26 N m 6 Kg d 0.8m

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Step 2

As given in the question that friction is very low so we can neglect the friction then the net work done on the box is done by force applied by man on the block,

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Work done byman on block,W Fd w-(26) (0.8) W 20.8 J

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Step 3

As the given system is open system where both mass and energy can be transferred from system to surrounding, but in given situation there is constant temperature in entire proce...

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As dT 0 dU 0 J

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Tagged in
SciencePhysics

Thermodynamics

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