A manufacturer knows that their items have a normally distributed lifespan, with a mean of 11.1 years, and standard deviation of 1.6 years. If you randomly purchase one item, what is the probability it will last longer than 10 years? (Give answer to 4 decimal places.)

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 4 years,…

A: Solution-: Given: We find, P[It will last longer than 4 years]=?

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 4.7…

A: It was given that a manufacturer knows that their items have a normally distributed lifespan. The…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 7 years,…

A: According to the given information, we have The distribution is normal. Mean = 7 years and Standard…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 4.6…

A: Given: Mean μ=4.6 Standard deviation σ=0.9

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 13.9…

A: Mean = 13.9 Standard deviation = 4.5

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 10.5…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 5.3…

A: Given that A manufacturer knows that their items have a normally distributed lifespan, with a mean…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 8.7…

A: Given:-A manufacturer knows that their items have a normally distributed lifespan, with a mean of…

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 12.6…

A: The provided information are:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 14.4…

A: Given that, Mean = 14.4 Standard deviation = 3.6

Q: A manufacturer knows that their items have a normally distributed lifespan with a mean of 4 years…

A: Given data A manufacturer knows that their items have a normally distributed lifespan with a mean of…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12.1…

A:

Q: A manufacturer knows that their items have a lengths that are approximately normally distributed,…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 13 years,…

A: GIVEN DATA,normal distribution μ= 13 years σ=2years  if you randomly purchase one item ,probability…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 7.9…

A: Here the distribution of lifespan follows N(7.9, 2.1). We need to find P(X>4).

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12.2…

A: Given: The mean lifespan of the items is μ=12.2 years. The standard deviation is σ=2.5 years. Let Y…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12.2…

A: We have given that, Normally distributed with mean = 12.2 . And Standard deviation = 1.9 . We have…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 13.9…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 2.8…

A: We have to find out given probabiity..

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 10.8…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 4.3…

A: GivenMean(μ)=4.3standard deviation(σ)=1.2

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 2.2…

A: It is an important part of statistics. It is widely used.

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 13.2…

A: As per guideline expert have to answer first question only since i have done all for you...

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 14.7…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 7.3…

A: Given:     = 7.3 , = 1.8   To find the probability, we need to find Z scores first.…

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 15.4…

A: We know it is normally distributed. So we can use the z - probability formula. z=x-μσ Here, μ -…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12 years,…

A: Given,mean(μ)=12standard deviation(σ)=2.7

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 14 years,…

A: Solution: Let X be the manufactures items have a normally distributed lifespan, with a mean of μ=14…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12.7…

A: Solution-: Given: μ=12.7,σ=1.6 We want to find, P(one item randomly selected, it will last longer…

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 12.5…

A: given  A manufacturer knows that their items have a normally distributed length, with a mean of 12.5…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 9.4…

A: Let "X" be the lifespan of the item in years.

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 8.9…

A: Given: Population meanμ=8.9Standard deviationσ=2.9

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 8.1…

A: Mean = 8.1 Standard deviation = 1.4

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 7.6…

A: Given Mean=7.6 Standard deviations=2.4

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12.7…

A: we have to find given probability.

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 7.3…

A: Please refer to the image below.

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 13.2…

A: In question, Given that A manufacturer knows that their items have a normally distributed lifespan,…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 4.5…

A: GivenMean(μ)=4.5standard deviation(σ)=1.5

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 3.4…

A: Let us consider X be a random variable which is used to denote the lifespan of the item. It is given…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 7.4…

A: It is given that, A manufacturer knows that their items have a normally distributed lifespan, with a…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 6 years,…

A: Given: Mean of a life span of an item μ= 6 years Standard deviation of a life span of an item σ= 1.4…

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 9.3 inches,…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 5.3…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 11.9…

A:

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 20 inches,…

A: Determine the Z score for the random variable X equals 23.1., The Z score for the random variable X…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12.9…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 11.9…

A: Let, X = Lifespan of items of a manufacturer. X~Normal(μ=11.9, σ2=1.72)

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 13.9…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 4.2…

A: From the provided information, Mean (µ) = 4.2 Standard deviation (σ) = 0.9 X~N (4.2, 0.9) Here X be…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 14.2…

A: Given that, Mean = 14.2 Standard deviation = 2.7

Contingency Table

A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.

Binomial Distribution

Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.