Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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### Solving Applications of Boyle's Law

**Problem:**
A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spherical air tank that measures 78.0 cm wide.

The biologist estimates she will need 1400 L of air for the dive. Calculate the pressure to which this volume of air must be compressed in order to fit into the air tank. Write your answer in atmospheres. Round your answer to 3 significant digits.

**Solution Steps:**
1. **Determine the Volume of the Spherical Tank:**
   - Given the diameter of the tank is 78.0 cm, the radius \( r \) is half of the diameter:
     \[
     r = \frac{78.0 \, \text{cm}}{2} = 39.0 \, \text{cm}
     \]
   - Volume \( V \) of a sphere is given by the formula:
     \[
     V = \frac{4}{3}\pi r^3
     \]
   - Converting the radius to meters for standard units (1 cm = 0.01 m):
     \[
     r = 39.0 \, \text{cm} \times 0.01 \, \text{m/cm} = 0.39 \, \text{m}
     \]
   - Calculating the volume:
     \[
     V = \frac{4}{3}\pi (0.39 \, \text{m})^3
     \]
     \[
     V \approx 0.249 \, \text{m}^3
     \]
     \( 1 \, \text{m}^3 = 1000 \, \text{L} \), so
     \[
     V \approx 249 \, \text{L}
     \]

2. **Apply Boyle’s Law:**
   Boyle’s Law states that \( P_1 V_1 = P_2 V_2 \).
   - Assuming the initial pressure \( P_1 = 1 \, \text{atm} \),
     \[
     1 \, \text{atm} \times 1400 \, \text{L} = P_2 \times 249 \, \text{L}
     \]
   - Sol
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Transcribed Image Text:### Solving Applications of Boyle's Law **Problem:** A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spherical air tank that measures 78.0 cm wide. The biologist estimates she will need 1400 L of air for the dive. Calculate the pressure to which this volume of air must be compressed in order to fit into the air tank. Write your answer in atmospheres. Round your answer to 3 significant digits. **Solution Steps:** 1. **Determine the Volume of the Spherical Tank:** - Given the diameter of the tank is 78.0 cm, the radius \( r \) is half of the diameter: \[ r = \frac{78.0 \, \text{cm}}{2} = 39.0 \, \text{cm} \] - Volume \( V \) of a sphere is given by the formula: \[ V = \frac{4}{3}\pi r^3 \] - Converting the radius to meters for standard units (1 cm = 0.01 m): \[ r = 39.0 \, \text{cm} \times 0.01 \, \text{m/cm} = 0.39 \, \text{m} \] - Calculating the volume: \[ V = \frac{4}{3}\pi (0.39 \, \text{m})^3 \] \[ V \approx 0.249 \, \text{m}^3 \] \( 1 \, \text{m}^3 = 1000 \, \text{L} \), so \[ V \approx 249 \, \text{L} \] 2. **Apply Boyle’s Law:** Boyle’s Law states that \( P_1 V_1 = P_2 V_2 \). - Assuming the initial pressure \( P_1 = 1 \, \text{atm} \), \[ 1 \, \text{atm} \times 1400 \, \text{L} = P_2 \times 249 \, \text{L} \] - Sol
---

### GASES
## Interconverting pressure and force

A cylinder measuring **2.4 cm wide** and **2.9 cm high** is filled with gas. The piston is pushed down with a steady force measured to be **13 N**.

![Diagram of the cylinder and piston](https://example.com/cylinder-piston-diagram) 

*Note: The diagram shows a cylinder filled with gas and a piston applying force to the gas.*

Calculate the pressure of the gas inside the cylinder. Write your answer in units of kilopascals. Round your answer to 2 significant digits.

---

#### Input Section:
![Input box](https://example.com/input-box) 
- Label: **kPa**
- Additional Options: 
  - Multiplication factor (×10)
  - Undo
  - Help

---

### Instructions for Calculation:
1. Calculate the area of the piston.
2. Use the formula \( \text{Pressure} = \frac{\text{Force}}{\text{Area}} \) to find the pressure.
3. Convert the pressure to kilopascals (kPa).
4. Round your answer to 2 significant digits.

---

##### Example Calculation:
1. **Calculate the Area (A):** 
   - Area of a circle = \( \pi r^2 \), where radius \( r = \frac{d}{2} = \frac{2.4 \, \text{cm}}{2} = 1.2 \, \text{cm} \)
   - \( A = \pi (1.2 \, \text{cm})^2 = \pi \times 1.44 \, \text{cm}^2 = 4.52 \, \text{cm}^2 \)
   
2. **Convert Area to m²:**
   - \( 4.52 \, \text{cm}^2 = 4.52 \times 10^{-4} \, \text{m}^2 \)
   
3. **Calculate the Pressure (P):**
   - \( P = \frac{F}{A} = \frac{13 \, \text{N}}{4.52 \times 10^{-4} \, \text{m}^2} = 2.88 \times 10^4 \, \text{Pa} \)
   
4. **Convert
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Transcribed Image Text:--- ### GASES ## Interconverting pressure and force A cylinder measuring **2.4 cm wide** and **2.9 cm high** is filled with gas. The piston is pushed down with a steady force measured to be **13 N**. ![Diagram of the cylinder and piston](https://example.com/cylinder-piston-diagram) *Note: The diagram shows a cylinder filled with gas and a piston applying force to the gas.* Calculate the pressure of the gas inside the cylinder. Write your answer in units of kilopascals. Round your answer to 2 significant digits. --- #### Input Section: ![Input box](https://example.com/input-box) - Label: **kPa** - Additional Options: - Multiplication factor (×10) - Undo - Help --- ### Instructions for Calculation: 1. Calculate the area of the piston. 2. Use the formula \( \text{Pressure} = \frac{\text{Force}}{\text{Area}} \) to find the pressure. 3. Convert the pressure to kilopascals (kPa). 4. Round your answer to 2 significant digits. --- ##### Example Calculation: 1. **Calculate the Area (A):** - Area of a circle = \( \pi r^2 \), where radius \( r = \frac{d}{2} = \frac{2.4 \, \text{cm}}{2} = 1.2 \, \text{cm} \) - \( A = \pi (1.2 \, \text{cm})^2 = \pi \times 1.44 \, \text{cm}^2 = 4.52 \, \text{cm}^2 \) 2. **Convert Area to m²:** - \( 4.52 \, \text{cm}^2 = 4.52 \times 10^{-4} \, \text{m}^2 \) 3. **Calculate the Pressure (P):** - \( P = \frac{F}{A} = \frac{13 \, \text{N}}{4.52 \times 10^{-4} \, \text{m}^2} = 2.88 \times 10^4 \, \text{Pa} \) 4. **Convert
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