Question
Asked Dec 17, 2019
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A mechanic pushes a 2.50 x 103- kg car from rest to a speed of v,
doing 5.00 x 103 J of work in the process. During this time, the
car moves 25.0 m. Neglecting friction between car and road,
find (a) v and (b) the horizontal force exerted on the car.

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Expert Answer

Step 1

(a)

The work done by the kinetic energy = kinetic energy of the car

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mv² = 5×10³J

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Step 2

Rearrange the above equation to obtain an equation for ...

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mv² = 5×10²J (2.5×10 kg )v² =10×10³J 10*J V 2.5x10 kg = 2m/s

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Science

Physics

Work,Power and Energy

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