# A motorboat cuts its engine when its speed is 10.7 m/s and coasts to rest. The equation describing the motion of the motorboat during this period is v = vie-ct, where v is the speed at time t, vi is the initial speed at t = 0, and c is a constant. At t = 19.5 s, the speed is 5.00 m/s.a) Find the constant c. b) What is the speed at t = 40.0 s?

Question
236 views

A motorboat cuts its engine when its speed is 10.7 m/s and coasts to rest. The equation describing the motion of the motorboat during this period is v = vie-ct, where v is the speed at time t, vi is the initial speed at t = 0, and c is a constant. At t = 19.5 s, the speed is 5.00 m/s.

a) Find the constant c.

b) What is the speed at t = 40.0 s?

check_circle

Step 1

a)

Equation for speed is,

Step 2
Step 3

Substituting the...

### Want to see the full answer?

See Solution

#### Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in