A parachutist  wants to design a parachute, such that a person weighing 150 lbs(667N) descends at a rate of 5.00 mph(2.23 m/s). To calculate the drag coefficient in kg/m, is the way to conceptualize the solution:1. At terminal velocity the drag force equals the force of gravity. Since the net forces are zero, there is no acceleration and the velocity is constant. 2. The drag constant b is not 1. It comes from the terminal velocity equation:V_term  = square root(mg/b)If you know the weight mg and the terminal velocity, then you can solve for b. Please help me to derive the solution by helping me to understand better.  I understand point 1.  But I don't understand clearly point 2?

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Asked Oct 13, 2019
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A parachutist  wants to design a parachute, such that a person weighing 150 lbs(667N) descends at a rate of 5.00 mph(2.23 m/s). To calculate the drag coefficient in kg/m, is the way to conceptualize the solution:

1. At terminal velocity the drag force equals the force of gravity. Since the net forces are zero, there is no acceleration and the velocity is constant.
 
2. The drag constant b is not 1. It comes from the terminal velocity equation:
V_term  = square root(mg/b)
If you know the weight mg and the terminal velocity, then you can solve for b.
 
Please help me to derive the solution by helping me to understand better.  I understand point 1.  But I don't understand clearly point 2?
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Expert Answer

Step 1

The given equation for the terminal velocity is

mg
b
terminal
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mg b terminal

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Step 2

Squaring the equation (1...

mg
[2]
terminal
b
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mg [2] terminal b

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