A parachutist wants to design a parachute, such that a person weighing 150 lbs(667N) descends at a rate of 5.00 mph(2.23 m/s). To calculate the drag coefficient in kg/m, is the way to conceptualize the solution: 1. At terminal velocity the drag force equals the force of gravity. Since the net forces are zero, there is no acceleration and the velocity is constant. 2. The drag constant b is not 1. It comes from the terminal velocity equation: V_term = square root(mg/b) If you know the weight mg and the terminal velocity, then you can solve for b. Please help me to derive the solution by helping me to understand better. I understand point 1. But I don't understand clearly point 2?
A parachutist wants to design a parachute, such that a person weighing 150 lbs(667N) descends at a rate of 5.00 mph(2.23 m/s). To calculate the drag coefficient in kg/m, is the way to conceptualize the solution: 1. At terminal velocity the drag force equals the force of gravity. Since the net forces are zero, there is no acceleration and the velocity is constant. 2. The drag constant b is not 1. It comes from the terminal velocity equation: V_term = square root(mg/b) If you know the weight mg and the terminal velocity, then you can solve for b. Please help me to derive the solution by helping me to understand better. I understand point 1. But I don't understand clearly point 2?
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter6: Applications Of Newton's Laws
Section: Chapter Questions
Problem 37P: An elevator filled with passengers has a mass of 1.70103kg . (a) The elevator accelerates upward...
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A parachutist wants to design a parachute, such that a person weighing 150 lbs(667N) descends at a rate of 5.00 mph(2.23 m/s). To calculate the drag coefficient in kg/m, is the way to conceptualize the solution:
1. At terminal velocity the drag force equals the force of gravity. Since the net forces are zero, there is no acceleration and the velocity is constant.
2. The drag constant b is not 1. It comes from the terminal velocity equation:
V_term = square root(mg/b)
If you know the weight mg and the terminal velocity, then you can solve for b.
Please help me to derive the solution by helping me to understand better. I understand point 1. But I don't understand clearly point 2?
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