- A parallel-plate capacitor initially has a potential difference of 400 V and is then disconnected from the charging battery. If the plate spacing is now halved (without changing Q), what is the new value of the voltage? a) 100 V b) 200 V c) 400 V d) 800 V e) 1600 V

- A parallel-plate capacitor initially has a potential difference of 400 V and is then disconnected from the charging battery. If the plate spacing is now halved (without changing Q), what is the new value of the voltage? a) 100 V b) 200 V c) 400 V d) 800 V e) 1600 V

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter21: Electric Fields

Section21.2: Applications Of Electric Fields

Problem 36PP

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Dielectric Constant Of Water

Water constitutes about 70% of earth. Some important distinguishing properties of water are high molar concentration, small dissociation constant and high dielectric constant.

Electrostatic Potential and Capacitance

An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.

Question

A parallel-plate capacitor initially has a potential difference of 400 V and is then disconnected from
the charging battery. If the plate spacing is now halved (without changing Q), what is the new value
of the voltage?
a) 100 V
b) 200 V
c) 400 V
d) 800 V
e) 1600 V

Expert Solution

Step 1

Given data:

The potential difference is V₁=400 V.
Plate spacing is d₂=0.5d₁.

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