A parallel-plate capacitor in air has a plate separation of 1.42 cm and a plate area of 25.0 cm2. The plates are charged to a potential difference of 265 V and disconnected from the source. The capacitor is then immersed in distilled water. Assume the liquid is an insulator. (a) Determine the charge on the plates before and after immersion. before pC after pC (b) Determine the capacitance and potential difference after immersion. Cf = F ΔVf = V (c) Determine the change in energy of the capacitor.nJ

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
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Chapter20: Electric Potential And Capacitance
Section: Chapter Questions
Problem 66P: A parallel-plate capacitor in air has a plate separation of 1.50 cm and a plate area of 25.0 cm2....
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A parallel-plate capacitor in air has a plate separation of 1.42 cm and a plate area of 25.0 cm2. The plates are charged to a potential difference of 265 V and disconnected from the source. The capacitor is then immersed in distilled water. Assume the liquid is an insulator.

(a) Determine the charge on the plates before and after immersion.
before pC
after pC

(b) Determine the capacitance and potential difference after immersion.
Cf = F
ΔVf = V

(c) Determine the change in energy of the capacitor.
nJ
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