A parcel of air moving in a straight tube with a constant acceleration of 24.00 m/s2 has a velocity of 13.0 m/s at 10:05:00 a.m. (a) What is its velocity at 10:05:01 a.m.? (b) At 10:05:04 a.m.? (c) At 10:04:59 a.m.? (d) Describe the shape of a graph of velocity versus time for this parcel of air. (e) Argue for or against the following statement: “Knowing the single value of an object’s constant acceleration is like knowing a whole list of values for its velocity.”

Question
Asked Oct 13, 2019
A parcel of air moving in a straight tube with a constant acceleration of 24.00 m/s2 has a velocity of 13.0 m/s at 10:05:00 a.m. (a) What is its velocity at 10:05:01 a.m.? (b) At 10:05:04 a.m.? (c) At 10:04:59 a.m.? (d) Describe the shape of a graph of velocity versus time for this parcel of air. (e) Argue for or against the following statement: “Knowing the single value of an object’s constant acceleration is like knowing a whole list of values for its velocity.”
check_circle

Expert Answer

Step 1

Given information:

The acceleration of the air parcel of air (a) = 24 m/s2

The velocity of the parcel at 10:05:00 am (v1) = 13 m/s

Step 2

The velocity of the parcel at 10:05:01am (v2) i.e. one sec after the given velocity:

Consider the first equation of motion:

v=u +at
Here "u" is the initial velocity (vi) and "v" is the required velocity (v2);
Substitute the corresponding values, we get:
V2 1324(1) = 37 m/s
help_outline

Image Transcriptionclose

v=u +at Here "u" is the initial velocity (vi) and "v" is the required velocity (v2); Substitute the corresponding values, we get: V2 1324(1) = 37 m/s

fullscreen
Step 3

The velocity of the parcel at 10:05:04am (v3) i.e. 4 sec after the give...

v=u +at
Here "u" is the initial velocity (vi) and "v" is the required velocity (v3);
Substitute the corresponding values, we get:
V3 1324(4) = 109 m/s
help_outline

Image Transcriptionclose

v=u +at Here "u" is the initial velocity (vi) and "v" is the required velocity (v3); Substitute the corresponding values, we get: V3 1324(4) = 109 m/s

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Science

Physics

Kinematics

Related Physics Q&A

Find answers to questions asked by student like you

Show more Q&A add
question_answer

Q: A 6.0x10–2 kg tennis ball moves at a speed of 12 m/s. The ball is struck by a racket, causing it to ...

A: Given information:Mass of the ball (m) = 6 × 10-2 kgInitial velocity of the ball (u) = 12 m/sFinal v...

question_answer

Q: Tarzan really wants to sweep Jane off her feet. He is standing on a tree branch 6m above and away fr...

A:  Given:Height of the tree branch from ground = 6 mDistance between the tree and the jane = 6 m 

question_answer

Q: The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 13.0 V and b = -6.70...

A: Given,

question_answer

Q: A rope is strung between two walls parallel to the floor.  A 35kg mass is hung from the rope at its ...

A: Given:Mass hung from the rope at its midpoint, m = 35 kgAngle made by rope w.r.t horizontal surface,...

question_answer

Q: os//newconnect.mheducation.com/flow/connect.html LS 1 x Search... 1G Saved Help Save & Exit Submit 1...

A: The expression to calculate the speed,

question_answer

Q: During which phase(s) can the Moon be seen high up in the sky during the day? [To answer the questio...

A: Phases of moon that are visible during the day are: Waxing crescent, first quarter, waxing gibbous, ...

question_answer

Q: Your car produces about 33kW of power to maintain a constant speed of 35 m/s on the highway. What av...

A: Give that power P = 33kWThe speed v = 35m/s

question_answer

Q: A graduate student leaves a cylinder of carbon dioxide sitting in the sun. The cylinder absorbs 25.2...

A: Given:Energy absorbed by cylinder = 25.2 JWork done by the piston = 12 J

question_answer

Q: Damped Oscillator Consider a 5. weakly damped oscillator with B < wo. There is a little difficulty d...

A: The graph sketch between x(t) and t is drawn below.