A particle is moving so that at any time t, its acceleration is 10t for t > or equal to 0. At the end of three seconds, the particle has moved 105 feet. What is its velocity at the end of 3 seconds?
Given that,
The acceleration of the particle is 10t for t ≥ 0.
The particle reached at the distance of 105 feet at t =3 sec.
Let s be the distance and v be the velocity at any time t and u be the particle initial velocity.
dv dt dv adt -=f adt 10tdt V-u 10 2 .....i
Integrate it again using...
ds dt ds vdt 105 ds vdt 105 105-05 ut 105 453u 105-45 ....ii u20
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