A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector 7 (2.00 m) î - (3.00 m)ĵ + (2.00 m) k, the force is F = Fxî + (7.00 N)ĵ - (6.00 N) Ê, and the corresponding torque about the origin is 7 = (4.00 N-m) î + (8.00 N-m) ĵ + (8.00 N-m) Ê. Determine F,x.

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter13: Rotation Ii: A Conservation Approach
Section13.6: Angular Momentum
Problem 13.2CE: Figure 13.24 shows a particle with momentum p. Using the coordinate systems shown, determine the...
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A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector
7 = (2.00 m) î - (3.00 m) ĵ + (2.00 m) k, the force is É = Fxî + (7.00 N)ĵ - (6.00 N) k, and the corresponding torque about the origin
is 7 = (4.00 N-m) î + (8.00 N-m)ĵ + (8.00 N-m) Ê. Determine Fx.
Number
i
Units
Transcribed Image Text:A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector 7 = (2.00 m) î - (3.00 m) ĵ + (2.00 m) k, the force is É = Fxî + (7.00 N)ĵ - (6.00 N) k, and the corresponding torque about the origin is 7 = (4.00 N-m) î + (8.00 N-m)ĵ + (8.00 N-m) Ê. Determine Fx. Number i Units
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