Question

A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector  r→ = (2.00 m) î - (3.00 m) ĵ + (2.00 m) k̂, the force is  F→ = Fx î + (7.00 N) ĵ - (6.00 N) k̂, and the corresponding torque about the origin is  τ→ = (4.00 N·m) î + (10.0 N·m) ĵ + (11.0 N·m) k̂. Determine Fx.

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