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Social ScienceA particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector r→ = (2.00 m) î - (3.00 m) ĵ + (2.00 m) k̂, the force is F→ = Fx î + (7.00 N) ĵ - (6.00 N) k̂, and the corresponding torque about the origin is τ→ = (4.00 N·m) î + (10.0 N·m) ĵ + (11.0 N·m) k̂. Determine Fx.
A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector r→ = (2.00 m) î - (3.00 m) ĵ + (2.00 m) k̂, the force is F→ = Fx î + (7.00 N) ĵ - (6.00 N) k̂, and the corresponding torque about the origin is τ→ = (4.00 N·m) î + (10.0 N·m) ĵ + (11.0 N·m) k̂. Determine Fx.
Expert Answer
Torque is a measure of the force that can cause an object to rotate about an axis. The expression for the torque is given by equation (1).
The position vector and the force vector is given in the question so that equating it with the torque the value of Fx can be found out.
Equating equation (4) and (5) the value...
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