A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector  r→ = (2.00 m) î - (3.00 m) ĵ + (2.00 m) k̂, the force is  F→ = Fx î + (7.00 N) ĵ - (6.00 N) k̂, and the corresponding torque about the origin is  τ→ = (4.00 N·m) î + (10.0 N·m) ĵ + (11.0 N·m) k̂. Determine Fx.

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Asked May 2, 2019
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A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector  r→ = (2.00 m) î - (3.00 m) ĵ + (2.00 m) k̂, the force is  F→ = Fx î + (7.00 N) ĵ - (6.00 N) k̂, and the corresponding torque about the origin is  τ→ = (4.00 N·m) î + (10.0 N·m) ĵ + (11.0 N·m) k̂. Determine Fx.

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Expert Answer

Step 1

Torque is a measure of the force that can cause an object to rotate about an axis. The expression for the torque is given by equation (1).

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Step 2

The position vector and the force vector is given in the question so that equating it with the torque the value of Fx can be found out.

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Step 3

Equating equation (4) and (5) the value...

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