A particular allele is mice is lethal with homozygous genotype, however heterozygous mice develop normally. Why does this the lethal allele remain the population?
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- In humans, the genetic disease cystic fibrosis is caused by a recessive allele (a). The normal (healthy) allele is dominant (A). What is the genotype of someone who has cystic fibrosis? What are the two different genotypes that a healthy person could have? If two people were both heterozygous for the cystic fibrosis gene, what fraction of their children would be likely to have this disease? Hint: Draw a Punnett square to figure it out.In mice, the presence of a dominant A allele results in the agouti pattern of fur color, whereas the aa homozygous recessive results in a solid color pattern. The presence of another dominant B allele results in black fur color, whereas the homozygous recessive bb results in brown fur color. The presence of a third dominant C allele is required for any color to be observed (brown or black), whereas the homozygous recessive cc results in lack of any color whatsoever (albino). What is the phenotype of a mouse with the following genotype? Aa bb cc albino Agouti color pattern and brown Solid color pattern and brown Agouti color pattern and black Solid color pattern and blackIn fruit flies, the dominant H allele gives rise to a hairless phenotype, hh gives rise to normal body bristles, and the HH homozygote condition is lethal during an embryonic stage. The presence of a dominant S allele suppresses the effect of the dominat H allele with respect to the body bristles phenotype such that normal body bristle phenotype is restored when only one dominant H allele is present (HH is lethal irrespective of the S or s alleles). The ss genotype has no effect over the H allele and the SS homozygote condition is also lethal during an embryonic stage. What would be the expected phenotypic outcomes among the surviving offspring from the following cross: HhSs X hhSs 2 normal body bristles: 1 hairless 7 normal body bristles: 2 hairless 1 normal body bristles: 1 hairless 3 normal body bristles: 1 hairless 5 normal body bristles: 1 hairless
- Female pig Emmy Lou (straight tail, white-haired) with the haplotype cH/Ch was mated to a curly-tailed black-haired male pig Wilhelm (ch/ch). Curly tails are due to the cc genotype and black hair is due to the hh genotype. From the choices shown below, which genotype would you expect to be the most frequent among their offspring? cH/ch cH/ch CH/ch CH/ch ch/ch ch/ch cc/hh cc/hh All genotypes are equally likely. All genotypes are equally likely.Skin color in humans is determined by polygenic inheritance, which means the more dominant alleles there are, the darker the skin color will be. A medium-toned skinned woman (AaBb) has a child with another medium-toned skinned man (AaBb). What is the probability of them having a very dark-toned skinned child? (Hint: the genotype is homozygous dominant)In humans, hair color and structure are determined by two independent pairs of genes. The dominant gene T determines dark hair color, and the recessive allele t - light hair; The dominant gene S determines the formation of curly hair, and its recessive allele t - straight hair. What kind of hair will the children have if the mother has light, straight hair, and the father has dark, curly hair (one of the pairs of traits is heterozygous for both parents)?
- If a trait is X-linked dominant, who would express the trait? A) females homozygous for the dominant allele and males hemizygous for the recessive allele B) heterozygous females and males hemizygous for the dominant allele C) females homozygous for the recessive allele and males hemizygous for the recessive allele D) females homozygous for the recessive allele and males hemizygous for the dominant allele E) significantly more females than malesIn genetics, the dash symbol (–) is a “wild card” that stands for either the dominant allele or the recessive allele; for example, A– means the individual has either the genotype AA or Aa. Two genes that undergo independent assortment affect coat color in Duroc pigs. Each gene has two alleles, one of which is dominant for coat color. Genotypes of the form A– B– are red, those of the form A– bb and aa B– are sandy, and genotype aa bb is white. What ratio of red:sandy:white is expected from the cross Aa Bb x Aa Bb?In Labrador dogs, coat color is controlled by the genotypes of two genes. In one gene, the dominant allele, B, produces black fur, and the recessive allele, b, produces brown fur. However, if a second gene possesses two recessive alleles, ee, the dog produces yellow fur, regardless of the genotype of the first gene. If two dogs that are heterozygous for both genes, BbEe mated, what would be the frequency of the three phenotypes, black, brown, and yellow?
- If a trait is X-linked recessive, who would express the trait? A) females homozygous for the dominant allele and males hemizygous for the recessive allele B) heterozygous females and males hemizygous for the dominant allele C) females homozygous for the recessive allele and males hemizygous for the recessive allele D) females homozygous for the recessive allele and males hemizygous for the dominant allele E) the same proportions of females and malesAs seen in the photo, Labradors come in three colors-- black, brown and yellow. What is the genetic basis for these different coat colors? One gene produces melanin, a pigment which is deposited in the dog's fur and makes the color dark. With this gene, allele B (black) is dominant to allele b. Only in the case of a recessive homozygote (bb) will the dog's phenotype be brown. The regulatory gene is separate from the melanin gene but it acts as a switch, either turning the melanin gene on or turning it off. Allele E is dominant and allows for the melanin to be deposited in the dog's fur ("on" switch), but if the switch gene is a recessive homozygote, the melanin is blocked ("off" switch) and a yellow dog is the result! Review the information on Labrador retrievers above. What are the phenotypic ratios of the F1 generation offspring of two dihybrids? Make sure to match the numbers with coat colors (e.g, which number in the ration goes with which color). Use a Punnett square to…As seen in the photo, Labradors come in three colors-- black, brown and yellow. What is the genetic basis for these different coat colors? One gene produces melanin, a pigment which is deposited in the dog's fur and makes the color dark. With this gene, allele B (black) is dominant to allele b. Only in the case of a recessive homozygote (bb) will the dog's phenotype be brown. The regulatory gene is separate from the melanin gene but it acts as a switch, either turning the melanin gene on or turning it off. Allele E is dominant and allows for the melanin to be deposited in the dog's fur ("on" switch), but if the switch gene is a recessive homozygote, the melanin is blocked ("off" switch) and a yellow dog is the result! 1. Two other Labradors mate and produce puppies. Their genotypes are Bbee and BbEe. What color are each parent and what are the phenotypic rations of their offspring in the F1 Generation? Show your work with a Punnett square.