A person is pushing a 8.58 kg block along a horiontal surface at a constant speed of 16.8 m/s. The person is applying a force of 8.05 N to the block at an angle of 35° above horizontal. If the block moves a distance of 3.5 m, what is the magnitude of the impulse parted upon the block by the person?

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A:

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A:

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A: Mass of particle: m =3 kgInitial velocity of particle: u = 2m/sFinal velocity of particle: v = -1…

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A:

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A: RecallI=impulse=∫t1t2Fdt=M(Vf-Vi)

Q: A soccer player kicks a soccer ball of mass 0.45 kg that is initially at rest. The player's foot is…

A:

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A:

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A:

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A:

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A: (a)   The impulse of the force can be determined by the area below the graph as below.

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A: Write the given values with the suitable variables. m=4.506 kgu=5.727 m/s Here, m is the mass and u…

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A: Here, ∆p=F∆tm∆v=F∆tF=m∆v∆t

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A:

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A:

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Q: 120 100 80 60 40 20 10 20 30 40 50 time /s

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A: Impulse is equal to chnage in momentum of the ball.

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A:

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A:

Q: A person is pushing a 8 kg block along a horiontal surface at a constant speed of 15.4 m/s. The…

A: Impulse due to gravity is = (Gravitational force)*(time ) Impulse = mg*time Impulse = m*g*(d/v)…

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A: The relationship of impulse and momentum is, I=m∆v I=1500(15-2.6) I=18600 kg m/s

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A: