A plane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. Assume that the plane reaches the required takeoff velocity at the end of the runway.What is the distance dlast traveled by the plane in the last second before taking off?

Question
Asked Oct 12, 2019
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A plane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. Assume that the plane reaches the required takeoff velocity at the end of the runway.

What is the distance dlast traveled by the plane in the last second before taking off?

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Expert Answer

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Step 1

Given values:

Acceleration of the plan, a = 5.00 m /s2

Length of runway, S = 1800 m

Initial velocity of the plane, u = 0

Step 2

Let the required takeoff velocity be v 

From third equation of motion:

12u2as
Plugging in the given values:
2 022x5x1800
v= v18000
= 134.16 m/s
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12u2as Plugging in the given values: 2 022x5x1800 v= v18000 = 134.16 m/s

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Step 3

Distance travelled by the plane in the last second before taking off...

1
S = ut +at
1
= vtat
last
Plugging in the given values:
1
d134.16x1 x5x (1)
=131.66 m
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Image Transcriptionclose

1 S = ut +at 1 = vtat last Plugging in the given values: 1 d134.16x1 x5x (1) =131.66 m

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