A plane leaves airport A and travels 540 miles to airport B on a bearing of N35 E. The plane later leaves airport B and travels to airport C 390 miles away on a bearing ofS76°E. Find the distance from airport A to airport C to the nearest tenth of a mile.The distance from airport A to airport C is about 771.1 miles.(Round to the nearest tenth as needed.)Question is complete.All parts showingSimilar QuestioneeO i

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Asked Nov 22, 2019
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Why should I use the law of cosine to solve this rather than the law of sines? 

A plane leaves airport A and travels 540 miles to airport B on a bearing of N35 E. The plane later leaves airport B and travels to airport C 390 miles away on a bearing of
S76°E. Find the distance from airport A to airport C to the nearest tenth of a mile.
The distance from airport A to airport C is about 771.1 miles.
(Round to the nearest tenth as needed.)
Question is complete.
All parts showing
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A plane leaves airport A and travels 540 miles to airport B on a bearing of N35 E. The plane later leaves airport B and travels to airport C 390 miles away on a bearing of S76°E. Find the distance from airport A to airport C to the nearest tenth of a mile. The distance from airport A to airport C is about 771.1 miles. (Round to the nearest tenth as needed.) Question is complete. All parts showing Similar Question ee O i

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Expert Answer

Step 1

Consider the distance from airport A to B is 540 miles in the direction of N-350E and distance from airport B to C is 390 miles in the direction of S-350E. Now, for the finding the distance from the airport A to C is calculated by use cosine rule because in the provided situation the when form the diagram of the respective problem observe that the triangle is formed and, in this triangle, there are two side and one angle is provided.

Step 2

Now draw the diagram for respective problem.

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N B 76 35* E W A C

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Step 3

According to Cosine Rule...

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c2 a2 b2-2ab cos C

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