Question
Asked Dec 23, 2019
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A plank 2.00 cm thick and 15.0 cm wide is firmly attached to the railing of a ship by clamps so that the rest of the board extends 2.00 m horizontally over the sea below. A man of mass 80.0 kg is forced to stand on the very end. If the end of the board drops by 5.00 cm because of the man’s weight, find the shear modulus of the wood.

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Expert Answer

Step 1

Given:

thickness = 2 cm

width = 15 cm

area of plank = 2 cm X 15 cm

mass = 80 kg

end of the board drops = 5 cm

force due to man = mg

                            = (80 X 9.8) N

Step 2

Shear modulus of the wood c...

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AL :G G =- AL A 80x9.8 G = 0.05 2×15×10¬ G = 40× 26.13×10* G =1045 ×10 G=1.05×10' Pa

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