Question

Asked Sep 7, 2019

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A point charge of -3.00 μC is located in the center of a spherical cavity of radius 6.60 cm inside an insulating spherical charged solid. The charge density in the solid is 7.35 × 10 −4 C/ m^3 .

Part A Calculate the magnitude of the electric field inside the solid at a distance of 9.40 cm from the center of the cavity. Express your answer with the appropriate units.

Part B Find the direction of this electric field.

Step 1

__Given:__

Charge at the centre of the spherical cavity, Q = -3.00 µC

Radius of the spherical cavity, R_{i }= 6.60 cm = 6.60 ×10^{-2 }m

Volume charge density of the spherical charged solid = 7.35×10^{-4 }C/m^{3}

Step 2

Consider a Gaussian sphere of radius R_{0} = 9.40cm = 9.40 ×10^{-2 }m from the centre of the spherical cavity.

Write the expression for charge enclosed by the Gaussian sphere:

Step 3

(A) Calculate the electric field at the distance ...

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