A poll of 2368 U.S. adults found that 40% regularly used Facebook as a news source. Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 90% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 95% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 99% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % The more error we allow, the less precise our estimate. Therefore, as the confidence level increases, the precision of our estimate decreases stays roughly the same increases

Q: Use the confidence interval to find the margin of error and the sample mean. (0.142,0.300) The…

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Q: Find the margin of error E that corresponds to the given statistics and confidence level.…

A: From the provided information, Confidence level = 98% Sample size (n) = 900 Success (p̂) = 0.40

Q: Use the confidence interval to find the margin of error and the sample mean. (0.276,0.440) The…

A: Given information- We have given the interval = (0.276, 0.440) We know that- Confidence interval =…

Q: Use the confidence interval to find the margin of error and the sample mean.   (0.096,0.300)

A: We are given a confidence interval  (0.096,0.300) to find margin of error and sample mean.

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A: Obtain the 96% confidence interval for the true population proportion. The 96% confidence interval…

Q: 12. A poll showed that 48 out of 120 randomly chosen graduates of California medical schools last…

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Q: a) Find a 90% confidence interval for the proportion of Americans who would agree with this. b)…

A: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Q: se the given degree of confidence and sample data to construct a confidence interval for the…

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Q: Find a 95% confidence interval for a mean, µ, where n = 324, x̄ = 2.7, s = .91, and se = .06.

A: Given: n = 324, x̄ = 2.7, s = .91, se = .06.

Q: Use the confidence interval to find the margin of error and the sample mean. (.228, 0.390)

A: We know that the Margin of error = (upper_limit - lower_imit )/2 and Sample mean = (upper limit +…

Q: se the sample data and confidence level given below to complete parts​ (a) through​ (d). A research…

A: Consider that p is the true population proportion of the respondents who felt vulnerable to identify…

Q: In each of Exercises, use the two-proportions plusfour z-interval procedure to find the required…

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Q: Use the confidence level and sample data to find a confidence interval for estimating the population…

A: Obtain the 98% confidence interval for the population mean. The 98% confidence interval for the…

Q: T.J. wants to estimate the percentage of college students who have taken out student loans. He…

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Q: A health magazine is interested in knowing the population proportion of people who eat fast food…

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Q: Use the confidence interval to find the margin of error and the sample mean. (0.328,0.430) The…

A: Given data,Lower limit=0.328Upper limit=0.430

Q: In each of Exercises, answer true or false to each statement concerning a confidence interval for a…

A: The margin of error for each confidence interval (E) is obtained as follows:

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: According to the provided information: The proportion can be calculated as:

Q: Use the confidence interval to find the margin of error and the sample mean. (0.186,0.350) The…

A: Solution: From the given information, the confidence interval is (0.186, 0.350).

Q: The principal of a school claims that 30% of grade 3 pupils stay in the playground after their…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…

Q: A survey of folk music fans yield this 95% confidence interval estimate of the proportion of fans…

A: Introduction:The 95% confidence interval for the requires proportion is (0.74, 0.86). So, lower…

Q: 5. Nancy surveyed 35 randomly selected students in her school about the number of hours they spend…

A: Here out of all students in the school Nancy selected 35 students and obtained a measure 1.2, we…

Q: Find the confidence level and α for a. an 85% confidence interval. b. a 95% confidence interval.

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Q: In a four-year psychedelic-mushroom experiment, 93 of the 300 subjects reported experiencing “strong…

A: Given information- We have given that 93 of the 300 subjects reported experiencing “strong or…

Q: In each of Exercises, use the one-proportion plus-four z-interval procedure to find the required…

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Q: . A survey of folk music fans yields this 95% confidence interval estimate of the proportion of fans…

A: The 95% confidence interval for proportion of fans who love music of David Wilcox is 0.74 to 0.86

Q: USE THE INFORMATION BELOW TO ANSWER QUESTIONS 4 THRU 6 In 2020 researchers took random samples to…

A: Givenconfidence interval is (0.013 , 0.049)conficence level = 96%

Q: A survey of folk music fans yields this 95% confidence interval estimate of the proportion of fans…

A: Solution: From the given information, the 95% confidence interval of the proportion of fans who love…

Q: f n=200 and X=80​, construct a 99​% confidence interval estimate for the population proportion.

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Q: the sample proportion of females is  x=118  n=164 P = .720  #1 Make a 95% confidence interval for…

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Q: Find the critical value that corresponds to 95% confidence for a mean and n = 35.

A: Given that - Find the critical value that corresponds to 95% confidence for a mean and n = 35.

Q: Construct a confidence interval of the population proportion at the given level of confidence. x=…

A: Given that sample size n = 1200 And number of successes x = 540 Confidence level = 98% = 0.98 At…

Q: 4. To estimate the mean retail price of designer jeans, a buyer sampled 19 retailers in New York…

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Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: It is given that n=195 and x=162. The sample proportion is 162/195 = 0.8308 The sample size is 195…

Q: Use the confidence interval to find the margin of error and the sample mean (0.586,0.730) The margin…

A: Given that,Confidence interval = (0.586, 0.730)

Q: Use the confidence interval to find the margin of error and the sample mean. (1.59,1.89)

A: Given data,Lower limit=1.59Upper limit=1.89Margin of error=?

Q: Using the t-table, give the confidence coefficient.   n=12 , CL = 95%

A: Given,   Sample size = 12 Confidence level = 95%   The objective is to find the confidence…

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a…

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Q: The Nielson television ratings used a sample of 2,000 homes to estimate the proportion of all homes…

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Q: and X = 96, construct a 90% confidence interval for the population proportion, p. Give your answers…

A: Given X=96 N=120

Q: In a survey, 1000 Grade 7 students were asked if they read storybooks. There were 318 who said Yes.…

A: Givenn=1000x=318p^=3181000=0.318Confidence interval = 95%

Q: A soft drink company surveys 500 shoppers and finds that 61% of shoppers prefer diet soda to regular…

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Q: a). Find a 93% confidence interval for p, the true crash risk (probability) for novice drivers, also…

A: For novice drivers, sample size n = 371, Number of crashes, X = 24 For expert drivers, sample size n…

Q: Find the sample size need to find the Population Proportion if the margin of error is 4%, the…

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Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Given data, n=195 x=126 p=x/n=126/195=0.646   z-value at 95% confidence is Zc=1.96

Q: In each of Exercises, use the one-proportion plus-four z-interval procedure to find the required…

A: In a survey, 836 out of 929online adults who are 18-29 years old said that they use social…

Q: Thirty randomly selected students took the calculus final. If the sample mean was 95 and the…

A: The summary of statistics is, The degree of freedom is, Critical value: By using the t-tables, the…

Q: The 99% confidence interval for the proportion of college students that prefer to work for a large…

A: We have given that that prefer to work for a large company is Sample size n =1500 Sample proportion…

Q: A major department store chain is interested in estimating the average amount its credit card…

A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…

Q: Researchers studied the mean egg length (in millimeters) for a bird population. After taking a…

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2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.