# A precipitation reaction occurs when 655 mL of 0.639 M Pb(NO2), reacts with 313 mL of 0.855 M KI, as shown by thefollowing equation.Pb(NO3)2(aq) 2 KI(aq)Pbl, (s) + 2 KNO3 (aq)Identify the limiting reactant.O Pb(NO3)2O KIO Pbl2Ο ΚNO,KNO3Calculate the theoretical yield of PbI, from the reaction.mass of Pbl,:Calculate the percent yield of PbI, if 48.0 g of Pbl, are formed experimentally.percent yield of PbI,:

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Asked Nov 13, 2019
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## Expert Answer

Step 1

The given volume and molarity of Pb(NO3)2 is 655 mL and 0.639 M.

The given volume and molarity of KI is 313 mL and 0.855 M.

The given reaction is as follows:

Step 2

It is known that 1 mL = 0.001 L.

Therefore, the volume of Pb(NO3)2 in L is 0.655 L.

Similarly, the volume of KI in L is 0.313 L.

The mathematical expression of molarity is,

Step 3

Put the given values in the formula to calculate the nu...

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