A projectile is fired into the air from the top of a cliff of height h=214 m above a valley. Its initial velocity is vo = 57.0 m/s at an angle 0 = 62.0° above the horizontal. How far from the base of the cliff does the projectile land? (Ignore any effects due to air resistance.) Range = ?

College Physics
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ISBN:9781305952300
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Chapter3: Motion In Two Dimensions
Section: Chapter Questions
Problem 39AP: A rocket is launched at an angle of 53.0 above the horizontal with an initial speed of 100. m/s. The...
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#2 using any of these equations
2. A projectile is fired into the air from the top of
a cliff of height h=214 m above a valley.
Its initial velocity is vo = 57.0 m/s at an
angle 0 = 62.0° above the horizontal.
How far from the base of the cliff does the
projectile land?
(Ignore any effects due to air resistance.)
Range = ?
Transcribed Image Text:2. A projectile is fired into the air from the top of a cliff of height h=214 m above a valley. Its initial velocity is vo = 57.0 m/s at an angle 0 = 62.0° above the horizontal. How far from the base of the cliff does the projectile land? (Ignore any effects due to air resistance.) Range = ?
Kinematics:
Vx = Vxo + axt
(x – xo) = vxot +;axt?
vž – vžo = 2a,(x – xo)
Vy = Vyo + Ayt
(y – yo) = vyot +ayt?
vž – vžo = 2a,(y – yo)
1
%3D
7 = xî + yĵ
di
う=
Vzî + vyĵ
dt
axî + ayĵ
dt
E =
= m
dt
di
(constant mass)
dt
EF = må, (constant mass)
Kinetic Friction Force:
fk = HxN
Static Friction Force: fs < HsN
g = 9.80 m/s²
Transcribed Image Text:Kinematics: Vx = Vxo + axt (x – xo) = vxot +;axt? vž – vžo = 2a,(x – xo) Vy = Vyo + Ayt (y – yo) = vyot +ayt? vž – vžo = 2a,(y – yo) 1 %3D 7 = xî + yĵ di う= Vzî + vyĵ dt axî + ayĵ dt E = = m dt di (constant mass) dt EF = må, (constant mass) Kinetic Friction Force: fk = HxN Static Friction Force: fs < HsN g = 9.80 m/s²
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