A proton (m = 1.67 x 10-27 kg) travels a distance of 3.2 cm parallel to a uniform electric field 3.4 x105 V/m between the plates shown in the figure. If the initial velocity is 1.5 x 105 m/s, find the magnitude of its final velocity in m/s. (* Ignore gravity) Round your answer to 0 decimal places.

A proton (m = 1.67 x 10-27 kg) travels a distance of 3.2 cm parallel to a uniform electric field 3.4 x105 V/m between the plates shown in the figure. If the initial velocity is 1.5 x 105 m/s, find the magnitude of its final velocity in m/s. (* Ignore gravity) Round your answer to 0 decimal places.

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter19: Electric Potential And Electric Field

Section: Chapter Questions

Problem 23PE: An electron is to be accelerated in a uniform electric field having a strength of 2.00106 V/m. (a)...

See similar textbooks

Related questions

Q: An electron moves horizontally with a speed of 1.55 X10^6 m/s between two horizontal parallel…

A: The horizontal speed of the electron in the horizontal direction is vx=1.55×106 m/s The length of…

Q: Part 1: A proton is accelerated from rest through a potential difference of 25599 V. What is the…

A: The kinetic energy of the proton , when it gets accelerated by a potential V=25599 V is calculated…

Q: 2- The poles of a 150V battery are connected to two parallel plates with an area of 30 cm? and a…

A: Given values: Voltage given for battery V = 150 V Plate's area A = 30 cm2 Distance between plates D…

Q: An Electron is emitted by heating a cathode and is accelerated by the potential difference of V…

A: The direction of motion of electron is shown as,

Q: Determine the acceleration of a proton (q = +e, m = 1.67 x 10^-27 kg) in an electric field of…

A: Given data: Charge on proton (q) = +e = +1.6×10-19 C Mass of proton (m) = 1.67×10-27 kg Electric…

Q: An electron is acted upon by a force of 3.00×10−15 NN due to an electric field. Find the…

A: A. Here v<<c, then the acceleration is

Q: The electric field between two parallel plates connected to a 100V battery is 2500N/C How far apart…

A: ∆V=100 VE=2500 N/C

Q: An Electron is emitted by heating a cathode and is accelerated by the potential difference of V…

Q: In a television picture tube, electrons strike the screen after being accelerated from rest through…

Q: In large CRT televisions, electrons are accelerated from rest by a potential difference of 23.88 kV…

Q: 2. The mass of an electron is 5x10 kg and its charge 1.6x10-1C C. For an accelerating voltage of…

A: Given The mass =5×10^10kg charge =1.6×10^-19C accelerating voltage of 2000v We have to find the…

Q: You have built a device that measures the temperature outside and displays it on a dial as a measure…

Q: An electron is fired at a speed v, = 4.2 x 105 m/s and at an angle 6 = 37° between two parallel…

A: Given data The speed of the electron is: v = 4.2×106 m/s The angle of projection between the two…

Q: The electrons in a cathode ray tube are accelerated from the cathode to the anode by a potential…

A: Given data, Initial potential differential = V Final potential difference = 4V

Q: There are approximately 2.97 trillion (2.97x10^12) electrons stored in a small, electrical component…

A: The charge is a scalar quantity therefore we can do scalar addition on them.

Q: In a television picture tube, electrons strike the screen after being accelerated from rest through…

Q: In a region containing an electric field, point A is at 750 volts and point B is at 950 volts. An…

A: Given data The voltage of point A is given as VA = 750 Volts. The voltage of point B is given as VB…

Q: The graph in Fig.9 show how one quantity, y, may vary with another quantity, x. ALNK B D X Which…

A: #49 The energy of a photon in terms of wavelength is, E=hcλ Here, h and c are constant and λ is…

Q: In a television picture tube, electrons strike the screen after being accelerated from rest through…

A: The electrostatic potential energy of electron is converted into the kinetic energyTherefore, we can…

Q: 6. Electron is accelerated by potential difference Up to 3,500KV. Determine the speed of the…

A: Given: V0 = 3500KVu = 0 To find: v Solution: Apply work-energy theorem, W = Kf - Ki =…

Q: What is the electric field between two parallel metal plates separated by 2.5 cm with a potential…

A: Separation between the plates is d = 2.5 cm = 0.025 m Potential difference between the plates is V =…

Q: A proton has a mass of about 1.673x10-27kg. If an electron is placed in a region of space within…

A: Mass of proton (m) = 1.673×10-27 kg Electric field strength (E) = 4.156 N/C distance moved (d) =…

Q: In the Millikan oil- drop apparatus set-up, a distance of 2.0 x 10^-3 m separates the plates.…

A: Given values: Separation between the plates, d=2.0×10-3 m Electric field, E=2.50×104 N/C Mass of the…

Q: Calculate the kinetic energy in Joules of these various objects E.K.=1/2mv^2 An electron travelling…

A: The equation of kinetic energy is: K=12mv2

Q: Suppose an electron (q= -e = -1.6 x 10^-19 C, m = 9.1 x 10^-31 kg) is accelerated from rest through…

A: Given: The potential difference is 5000 V. The mass of the electron is 9.1×10-31 kg. The charge on…

Q: 6. The diagram below illustrates how an ion is accelerated from rest. The ion in question has a mass…

Q: A proton has a mass of about 1.673x10-27kg. If an electron is placed in a region of space within…

A: Solution: Force on a charge q, placed in an uniform electric field E is given as F=qE→…

Q: Suppose an electron (q = - e = -1.6 × 10¬19 C,m=9.1 × 10¬3' kg) is accelerated from rest through a…

A: Given that the value of charge and mass and voltage (Vab). Then We have to determine the value of…

Q: 12. A muon enters an electric field at a speed of 5x106 m/s. The electric field slows it uniformly…

Q: Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED…

A: The electric potential and electric field intensity for the parallel plate capacitor is related by…

Q: In a typical television or in an older computer monitor's cathode ray tube (CRT), electrons are…

A: charge of electron (q) = -1.6 ×10-19 C Potential difference through which the electrons are…

Q: What is the speed of an electron after being accelerated from rest through a 20 x 106 V potential…

A: 12mv2=eV v=2eVm

Q: Table 2: For the – InC Measured electric field from the simulation Distance (cm) Distance (m)…

A: Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and…

Q: Complete the following statements: After some rather exhausting counting (and a rather tall tale), a…

Q: There are approximately 2.31 trillion (2.31 x 102) electrons stored in a small, electrical component…

A: no of electron present = 2.31 x 1012 charge on electron = 1.60 x 10-19 C WE know that q = n e

Q: What voltage is needed to accelerate an alpha particle from rest to 0.2% the speed of light, that is…

A: Force on charge particles F=qE

Q: 7.57 What is the head loss at the outlet of the pipe that dis- charges water into the reservoir at a…

Q: A positron (a particle with a charge +e and a mass equal to that of electron) that is accelerated…

Q: An electron is projected horizontally at a speed of 2.5 x 10*6 m/s between two plates. metal…

Q: If a 0.2 kg object (carrying a -250 μC) is released from rest 10 m from a 500 μC, what will be its…

Q: Calculate for the speed of the proton whose energy in motion 32 x 10- keV. 6.19 х 1013 т 7.8 x 105 m

Q: Two parallel plates are situated 4cm apart in vacuum and have a potential difference of 200V between…

A: Since we only answer up to three sub-parts, we will answer the first three. Please resubmit the…

Q: What potential difference must be developed across the terminals of a lamp in order for a flow of…

A: Given Charge is q=0.05 C Energy is E= 6 J

Q: Suppose an electron is accelerated from rest through a potential difference of 100,000 volts.…

Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

A proton (m = 1.67 x 10-27 kg) travels a distance of 3.2 cm
parallel to a uniform electric field 3.4 x105 V/m between
the plates shown in the figure. If the initial velocity is 1.5 x
105 m/s, find the magnitude of its final velocity in m/s. (*
Ignore gravity)
Round your answer to 0 decimal places.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

An electron is to be accelerated in a uniform electric field having a strength of 2.00106 V/m. (a) What energy in keV is given to the electron if it is accelerated through 0.400 m? (b) Over what distance would it have to be accelerated to increase its energy by 50.0 GeV?
An evacuated tube uses an accelerating voltage of 40 kV to accelerate electrons to hit a copper plate and produce x rays. Non-relativistically, what would be the maximum speed of these electrons?
Review. From a large distance away, a particle of mass 2.00 g and charge 15.0 C is fired at 21.0 m/s straight toward a second particle, originally stationary but free to move, with mass 5.00 g and charge 8.50 C. Both particles are constrained to move only along the x axis. (a) At the instant of' closest approach, both particles will be moving at the same velocity. F'ind this velocity. (b) Find the distance of closest approach. After the interaction, the particles will move far apart again. At this time, find the velocity of (c) the 2.00-g particle and (d) the 5.00-g particle.
Two metal spheres of identical mass m = 4.00 g are suspended by light strings 0.500 m in length. The left-hand sphere carries a charge of 0.800 C, and the right-hand sphere carries a charge of 1.50 C. What is the equilibrium separation between the centers of the two spheres?
Why is the following situation impossible? An electron enters a region of uniform electric field between two parallel plates. The plates are used in a cathode-ray tube to adjust the position of an electron beam on a distant fluorescent screen. The magnitude of the electric field between the plates is 200 N/C. The plates are 0.200 m in length and are separated by 1.50 cm. The electron enters the region at a speed of 3.00 106 m/s, traveling parallel to the plane of the plates in the direction of their length. It leaves the plates heading toward its correct location on the fluorescent screen.
A constant electric field accelerates a proton from rest through a distance of 2.00 m to a speed of 1.50 105 m/s. (a) Find the change in the protons kinetic energy. (b) Find the change in the systems electric potential energy. (c) Calculate the magnitude of the electric field.
Calculate the speed of a proton that is accelerated from rest through an electric potential difference of 120 V. Calculate the speed of an electron that is accelerated through the same electric potential difference.
Rocket observations show that dust particles in Earths upper atmosphere are often electrically charged. (a) Find the distance separating two dust particles if each has a charge of +e and the Coulomb force between them has magnitude 1.00 1014 N. (b) Calculate the mass of one of the dust panicles if this Coulomb force would accelerate it at 4.50 108 m/s2. (In the upper atmosphere, effects from other nearby charges typically result in a small net force and acceleration.)
A simple and common technique for accelerating electrons is shown in Figure 18.55, where there is a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving. (a) Calculate the acceleration of the electorn if the field strength is 2.50104 N/C. (b) Explain why the electron will not be pulled back to the positive plate once it moves through the hole.
A Van de Graaff accelerator utilizes a 50.0 MV potential difference to accelerate charged particles such as protons. (a) What is the velocity of a proton accelerated by such a potential? (b) An electron?
Find the radius of curvature of the path of a 25.0-MeV proton moving peipendicularly to the 1,20-T field of a cyclotron.
Review. Two insulating spheres have radii 0.300 cm and 0.500 cm, masses 0.100 kg and 0.700 kg, and uniformly distributed charges 2.00 C and 3.00 C. They are released from rest when their centers are separated by 1.00 m. (a) How fast will each be moving when they collide? (b) What If? It the spheres were conductors, would the speeds be greater or less than those calculated in part (a)? Explain.