A proton (q = 1.60 × 1019 C) moves 10.0 cm on a path parallel to the direction of a uniform electric field of strength 3.0 N/C. What is the change in electrical potential energy?

University Physics Volume 2
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Chapter7: Electric Potential
Section: Chapter Questions
Problem 39P: Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero...
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1. A proton (q =1.60 × 1019 C) moves 10.0 cm on a path parallel to the direction of a uniform electric field of
strength 3.0 N/C. What is the change in electrical potential energy?
Transcribed Image Text:1. A proton (q =1.60 × 1019 C) moves 10.0 cm on a path parallel to the direction of a uniform electric field of strength 3.0 N/C. What is the change in electrical potential energy?
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