  # A psychologist hypothesizes that the children with type K personality score higher than the children with type R personality on a memory test. The estimated standard error turned out to be 0.9, while the mean score of type K children was 18.8 and the mean score for type R children was 21.3. What is the t-score?a. t = (18.8 - 21.3)/0.9 = 2.78b. t = (18.8 - 21.3)(0.3) = 8.33c. t = (18.8 - 21.3)/0.92 = 3.09d. t = (18.8 - 21.3)(2)(0.9) = 1.39

Question

A psychologist hypothesizes that the children with type K personality score higher than the children with type R personality on a memory test. The estimated standard error turned out to be 0.9, while the mean score of type K children was 18.8 and the mean score for type R children was 21.3. What is the t-score?

a. t = (18.8 - 21.3)/0.9 = 2.78

b. t = (18.8 - 21.3)(0.3) = 8.33

c. t = (18.8 - 21.3)/0.9= 3.09

d. t = (18.8 - 21.3)(2)(0.9) = 1.39

check_circleExpert Solution
Step 1

Test statistic:

The t-score for two sample t-test is given by:

Step 2

Where X1- bar and X2 -bar are the mean  of the two samples. SE represents the estimated standard error.

Step 3

Find the value of t-score:

The test claim that children with type K personality score higher than the children with type R personality on a memory test.

The mean score for type K and R children are 18.8 and 21.3 respectively. That is, is X1-bar = 18.8and X2-bar = 21.3 respectively. The null hypothesis fo...

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