A radionctive substance follows the decay equation A = kA. If 20% of the substance disappears in 9 years, whaut is its half-life t (in years)? (Use symbolic notation and fractions where needed.) years

Q: The amount of​ carbon-14 present in a paint after t years is given by y=yoe^−0.00012t. The paint…

A: Given amount of carbon-14 present in a paint after t years is            y = y0 e^- 0.00012t If t= 0…

Q: Bethany needs to borrow $12,000. She can borrow the money at 5.5% simple interest for 3 yr or she…

A: Answer is mentioned below

Q: In 2000, 50 grams of radium were stored. The half-life of radium is 1,620 years. How many grams of…

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Q: The population

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Q: The amount of​ carbon-14 present in animal bones after t years is given by ​P(t)=P 0 e^-0.00012t A…

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Q: The amount of carbon-14 present in animal bones after t years is given by P(t) = Poe -0.00012t. A…

A: answer is in next step. please give a like !!

Q: An unknown sample contains radioactive element U-235. If the original amount present is 3500 atoms,…

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Q: Radioactive iodine treatment is so successful at treating hyperthyroidism that it has virtually…

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Q: In the early 1960s, radioactive strontium-90 was released during atmospheric testing of nuclear…

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Q: $15,000 is invested in an account that pays 5% interest. How much money will you have in the account…

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Q: In the year 1950, the world population was 2.56 billion people. In 1960, the population grew to 3.04…

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Q: Mary needs to borrow $11,000. She can borrow the money at 6.5% simple interest for 5 yr or she can…

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Q: If Sandago has a present population of 70,000, and thr population is increasing by 3% each year.…

A: By using the formula you can solve the problem as follows :

Q: in 2008 the price of a new Mazda, RX-8, four door coupe was $28,900. Assume that the value of the…

A: Let's find.

Q: The half-life of radium is approximately 1690 years. A laboratory has 50 milligrams of radium. How…

A: Given that, the half life of radium is approximately 1690 years. Use the formula N=N012n to find the…

Q: Delta invested 25, 000 pesos in a bank that earns 2.5% annual interest compounded continuously. How…

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Q: The half-life of carbon-14, 14C, is approximately 5,730 years. A bone fragment is estimated to have…

A: Given information: Initial amount=Q0=7 mgHalf life=t12=5730 years

Q: 2. At the start of the experiment, there are 400 bacteria. If the bacteria follow an exponential…

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Q: . Radioactive Radon After 3 days a sample of radon-222 has decayed to 58% of its original amount.…

A: Given, mass of radon-222 decayed 58% of original amount m(t)=m(3)=0.58m0 0.58m0=m0e3ke3k=0.58 take…

Q: A certain radioactive isotope decays according to the model y(t) = yo e-0.0002, where y(t)…

A: according to our guidelines we can answer only three subparts, or first question and rest can be…

Q: At the beginning of an experiment, a scientist has 372 grams of radioactive goo. After 195 minutes,…

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Q: H. The population is 900 in the beginning and will grow by 300 people during the next two years.

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Q: 12. A 50 mg sample of radioactive iodine decays to 23mg after 12 minutes. a. Determine the half-life…

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Q: The half-life of radioactive strontium-90 is approximately 31 years. In 1960, radioactive…

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Q: In the formula A(1) = Pe" for continuously compound inter- est, the letters P, r, and i stand for.…

A: The given formula is At=Pert. Here,  P=Principal r=rate of interest t=time in years. At=Amount after…

Q: nt Use the formula A =p(1+)" $750 invested for 5 years at 9% compounded semiannually produces $1000…

A: Please rate

Q: The amount of​ carbon-14 present in a paint after t years is given by y=yoe−0.00012t. The paint…

A: Exponential decay

Q: Bethany needs to borrow $10,000. She can borrow the money at 5.5% simple interest for 4 yr or she…

A: A. Simple interest for an amount P, at an interest rate of r (in decimals) per annum and for T years…

Q: 37. Use the given formulas, find the balance A when $10,000 is invested at 2% rate for 10 years and…

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Q: The half-life of radioactive strontium-90 is approximately 31 years. In 1963, radioactive…

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Q: A jet ski that costs $13,200 when new will have no salvage value after 6 years. Find its annual rate…

A: A jet ski that costs $13,200 when new will have no salvage value after 6 years.   Formula: Rate of…

Q: A saving account deposit of $150 is to earn 6.5% compound continuously. To the nearest year how many…

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Q: Bethany needs to borrow $11,000. She can borrow the money at 5.5% simple interest for 6 yr or she…

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Q: You deposit $2000 in an account earning 7% interest compounded continuously. How much will you have…

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Q: 22)  A linen artifact found in a crypt contains 95 percent of the carbon-14 that is present in…

A: Given that: Half life of carbon=5730 yearsPercentage of carbon present=95%

Q: years, 20% of a radioactive element decays. Find its half-life. (Round your answer to one decimal…

A: Given query is to find the half life if the substance

Q: How much of a 102-mg sample would be remaining after 7 years? b) If the half-life were shorter than…

A: In this question, we use the application of differential equation to calculate the amount of lead…

Q: 11. The current population in Passaic is 9,000. If the population, P, increases by 15% each year,…

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Q: |The amount A(t) of atmospheric pollutants in a certain mountain valley grows naturally and is…

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Q: (5) Radioactive decay is measured in terms of "half-life", which is the number of years required for…

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Q: The half-life of Radium-226 is 1590 years. If a sample contains 300 mg, how many mg will remain…

A: Radioactivity equation is given by,           N =NO e-λt  where, NO = Initial quantity…

Q: Element X decays radioactively with a half life of 8 minutes. If there are 460 grams of Element X,…

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Q: Al needs to borrow $15,000 to buy a car. He can borrow the money at 6.7% simple interest for 5 yr or…

A: a)From the given,P = $15,000r = 6.7% = 6.7/100 = 0.067n = 5 yrThen simple interest is,S.I = Pnr

Q: e number of years required for a $2000 investment to double at a 10% interest rate coumpounded…

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Q: A new car that sells for $19,000 depreciates (decreases in value) 21% each year. What is the decay…

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Q: A certain isotope decays so that the amount A remaining after t years is given by: A = Ao e-0.03t…

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Q: Half-Life decay Rate,k 2208 years

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Q: The amount of carbon-14 present in animal bones t years after the animal's death is given by P(t) =…

A: given p(t) = p0e-0.00012097tand ivory tusk has lost 18% of carbon-14p(t) = po-18100pop(t) = 0.82p0t=…