# A random sample of n observations is selected from a normal population to test the null hypothesis that u= 10. Specify the rejection region for each of the followingcombinations of H, a, and n.a. Ha 10, o= 0.05; n = 14b. Ha > 10; a= 0.10; n = 24C. Ha:d. Ha: 10; a= 0.10; n = 1 1e. Ha u 10; a 0.01 ; n = 221. Η. με 10 , α-0.05, n-510, a= 0.01; n = 12frect: 0c. Select the correct choice below and fill in the answer box within your choice.y(Round to three decimal places as needed.)O A. ItO B. tO C. tClick to select and enter your answer(s) and then click Check Answer3 partsremainingCheck AnswerClear AllTarms of Llcetion Inc All rights rase2019 Pearson lConvriahthere to search

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15 views help_outlineImage TranscriptioncloseA random sample of n observations is selected from a normal population to test the null hypothesis that u= 10. Specify the rejection region for each of the following combinations of H, a, and n. a. Ha 10, o= 0.05; n = 14 b. Ha > 10; a= 0.10; n = 24 C. Ha: d. Ha: 10; a= 0.10; n = 1 1 e. Ha u 10; a 0.01 ; n = 22 1. Η. με 10 , α-0.05, n-5 10, a= 0.01; n = 12 frect: 0 c. Select the correct choice below and fill in the answer box within your choice. y (Round to three decimal places as needed.) O A. It O B. t O C. t Click to select and enter your answer(s) and then click Check Answer 3 parts remaining Check Answer Clear All Tarms of Llce tion Inc All rights rase 2019 Pearson l Convriaht here to search fullscreen
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Step 1

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Step 2

(a)Rejection region:

It is given that test is two tailed. α = 0.05, n=14.

Note that the Excel formula =T.INV.2T (0.05,13) directly gives the value of the higher critical value, t0.025­ as 2.160. Thus, the rejection region (for rejecting the relevant null hypothesis) is as follows:

Step 3

(b)Rejection region:

It is given that test is right tailed. α = 0.10, n=24.

Note that the Excel formula =T.INV(0.90,23) directly gives the value of the higher critical value, t0.10 as 1.31...

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