A random sample of n observations is selected from a normal population to test the null hypothesis that u= 10. Specify the rejection region for each of the followingcombinations of H, a, and n.a. Ha 10, o= 0.05; n = 14b. Ha > 10; a= 0.10; n = 24C. Ha:d. Ha: 10; a= 0.10; n = 1 1e. Ha u 10; a 0.01 ; n = 221. Η. με 10 , α-0.05, n-510, a= 0.01; n = 12frect: 0c. Select the correct choice below and fill in the answer box within your choice.y(Round to three decimal places as needed.)O A. ItO B. tO C. tClick to select and enter your answer(s) and then click Check Answer3 partsremainingCheck AnswerClear AllTarms of Llcetion Inc All rights rase2019 Pearson lConvriahthere to search

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Asked Nov 12, 2019
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A random sample of n observations is selected from a normal population to test the null hypothesis that u= 10. Specify the rejection region for each of the following
combinations of H, a, and n.
a. Ha 10, o= 0.05; n = 14
b. Ha > 10; a= 0.10; n = 24
C. Ha:
d. Ha: 10; a= 0.10; n = 1 1
e. Ha u 10; a 0.01 ; n = 22
1. Η. με 10 , α-0.05, n-5
10, a= 0.01; n = 12
frect: 0
c. Select the correct choice below and fill in the answer box within your choice.
y
(Round to three decimal places as needed.)
O A. It
O B. t
O C. t
Click to select and enter your answer(s) and then click Check Answer
3 parts
remaining
Check Answer
Clear All
Tarms of Llce
tion Inc All rights rase
2019 Pearson l
Convriaht
here to search
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A random sample of n observations is selected from a normal population to test the null hypothesis that u= 10. Specify the rejection region for each of the following combinations of H, a, and n. a. Ha 10, o= 0.05; n = 14 b. Ha > 10; a= 0.10; n = 24 C. Ha: d. Ha: 10; a= 0.10; n = 1 1 e. Ha u 10; a 0.01 ; n = 22 1. Η. με 10 , α-0.05, n-5 10, a= 0.01; n = 12 frect: 0 c. Select the correct choice below and fill in the answer box within your choice. y (Round to three decimal places as needed.) O A. It O B. t O C. t Click to select and enter your answer(s) and then click Check Answer 3 parts remaining Check Answer Clear All Tarms of Llce tion Inc All rights rase 2019 Pearson l Convriaht here to search

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Step 2

(a)Rejection region:

It is given that test is two tailed. α = 0.05, n=14.

Note that the Excel formula =T.INV.2T (0.05,13) directly gives the value of the higher critical value, t0.025­ as 2.160. Thus, the rejection region (for rejecting the relevant null hypothesis) is as follows:

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Rejection region is, >2.160

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Step 3

(b)Rejection region:

It is given that test is right tailed. α = 0.10, n=24.

Note that the Excel formula =T.INV(0.90,23) directly gives the value of the higher critical value, t0.10 as 1.31...

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