Question

Asked Oct 15, 2019

A random sample of size 30 from a normal population yields = 39 and s = 4.9. The lower bound of a 95 percent confidence interval is

(Round off upto 2 decimal places).

Step 1

**Note:**

Hey there! Thank you for the question. In the first line, it is written “A random sample of size 30 from a normal population yields = 39”, which does not make sense. Logically, it can be the sample mean. Thus, we have assumed that the actual information is, *x̅* = 39, and solved the problem.

Step 2

**Introduction:**

The 100 (1 – *α*) % confidence interval for the population mean, *μ*, for given sample standard deviation, *s* is: (*x̅* – (*tα*/2; *n* – 1) (*s/√n*), *x̅* + (*tα*/2; *n* – 1) (*s/√n*)).

Here, *n* is the sample size, *x̅* is the sample mean, and *tα*/2; *n* – 1 is the critical value of the *t*-distribution with (*n* – 1) degrees of freedom, above...

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