Question

Asked Mar 22, 2019

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A random sample of 336 medical doctors showed that 160 had a solo practice.

(a) Let *p* represent the proportion of all medical doctors who have a solo practice. Find a point estimate for *p*. (Use 3 decimal places.)

(b) Find a 95% confidence interval for*p*. (Use 3 decimal places.)

(b) Find a 95% confidence interval for

lower limit | |

upper limit |

What is the margin of error based on a 95% confidence interval? (Use 3 decimal places.)

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Step 1

**(a) Obtain a point estimate for p**

Here, a randm sample of 336 (*n*) medical doctors showed that 160 (*x*) had a solo practice.

The point estimate is obtained as **0.476** from the calculation given below:

Step 2

**(b) Obtain the critical value**

From, the standard normal table, the critical value at 5% level is ±1.96.

Step 3

**Find a 95% confidence interval for p.**

The 95% confidence interval is **(0.423, 0.529)**, the lower limit is **0.423** an...

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