Question
Asked Nov 20, 2019
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A reaction of 44.7 g of Na and 35.7 g of Br yields 45.2 g of NaBr. What is the percent yield?
2 Na(s)Br2(g)
2 NaBr(s)
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A reaction of 44.7 g of Na and 35.7 g of Br yields 45.2 g of NaBr. What is the percent yield? 2 Na(s)Br2(g) 2 NaBr(s)

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Expert Answer

Step 1

Given:

Mass of Na = 44.7 g.

Mass of Br2 = 35.7 g.

Actual yield of NaBr = 45.2 g

Balanced chemical reaction is given by:

2Na(s)Br2 (g) -»2NaBr
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2Na(s)Br2 (g) -»2NaBr

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Step 2

Calculation for moles of Na:

mass
number of moles
molar mass
44.7 g
number of moles =
22.989 g/mol
number of moles = 1.944 moles.
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mass number of moles molar mass 44.7 g number of moles = 22.989 g/mol number of moles = 1.944 moles.

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Step 3

Calculation for moles of...

mass
number of moles
molar mass
35.7 g
number of moles =
159.808 g/mol
number of moles
0.2234 moles
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mass number of moles molar mass 35.7 g number of moles = 159.808 g/mol number of moles 0.2234 moles

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