A recent study showed that the average number of sticks of gum a person chews in a week is 11. A college student believes that the guys in his dormitory chew less gum in a week. He conducts a study and samples 14 of the guys in his dorm and finds that on average they chew 10 sticks of gum in a week with a standard deviation of 3.1. Test the college student's claim at a=0.01. The correct hypotheses would be: Ο H:μ < 11 HA: µ > 11 (claim) Ο Η: μ 2 11 HA: µ < 11 (claim) Ο Η0: μ 11 HA: µ + 11 (claim) Since the level of significance is 0.01 the critical value is -2.65 The test statistic is: (round to 3 places) The p-value is: (round to 3 places) The decision can be made to: O reject Ho O do not reject Ho The final conclusion is that: O There is enough evidence to reject the claim that less gum in a week. There is not enough evidence to reject the claim that less gum in a week. O There is enough evidence to support the claim that less gum in a week. O There is not enough evidence to support the claim that less gum in a week.

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A recent study showed that the average number of sticks of gum a person chews in a week is 11. A college
student believes that the guys in his dormitory chew less gum in a week. He conducts a study and samples
14 of the guys in his dorm and finds that on average they chew 10 sticks of gum in a week with a standard
deviation of 3.1. Test the college student's claim at a=0.01.
The correct hypotheses would be:
Ο H: μ< 11
HA: µ > 11 (claim)
Ho: μ Σ11
HA:µ < 11 (claim)
Ο Η: μ = 11
HA:H + 11 (claim)
Since the level of significance is 0.01 the critical value is -2.65
The test statistic is:
(round to 3 places)
The p-value is:
(round to 3 places)
The decision can be made to:
O reject Ho
do not reject Họ
The final conclusion is that:
There is enough evidence to reject the claim that less gum in a week.
There is not enough evidence to reject the claim that less gum in a week.
There is enough evidence to support the claim that less gum in a week.
There is not enough evidence to support the claim that less gum in a week.
Transcribed Image Text:A recent study showed that the average number of sticks of gum a person chews in a week is 11. A college student believes that the guys in his dormitory chew less gum in a week. He conducts a study and samples 14 of the guys in his dorm and finds that on average they chew 10 sticks of gum in a week with a standard deviation of 3.1. Test the college student's claim at a=0.01. The correct hypotheses would be: Ο H: μ< 11 HA: µ > 11 (claim) Ho: μ Σ11 HA:µ < 11 (claim) Ο Η: μ = 11 HA:H + 11 (claim) Since the level of significance is 0.01 the critical value is -2.65 The test statistic is: (round to 3 places) The p-value is: (round to 3 places) The decision can be made to: O reject Ho do not reject Họ The final conclusion is that: There is enough evidence to reject the claim that less gum in a week. There is not enough evidence to reject the claim that less gum in a week. There is enough evidence to support the claim that less gum in a week. There is not enough evidence to support the claim that less gum in a week.
Expert Solution
Step 1

Given information-

Population mean, μ = 11

Sample size, n = 14

Sample mean, M = 10

Sample standard deviation, s = 3.1

Significance level, α = 0.01

Hypothesis Formulation-

Null Hypothesis, H0: μ ≥ 11

Alternate Hypothesis, Ha: μ < 11

Since here population standard deviation is unknown so using t-test statistics

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