A rectangular box of crackers has a volume in cubic centimeters that can be modelled by the function  V(x)=x^3-38x^2+367x-1050   1. Determine the dimensions of the box in terms of  X 2. What are the dimensions of the box when X=30cm 3. Graph V(x) for the interval (0,30)

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A: Given,          The function is fx=x4+3x3-4x2-12x .

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A:

Q: -5- - fx – 3;x 0 f(x):

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A: Solution:

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A: Please refer the attached image for complete solution.

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A: Cube:

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A: Given: y=4x3+21x2+36x-20y'=12x2+42x+36=0⇒2x2+7x+6=0⇒x=-2   or  x=-32

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A: Concept - Any relation/equation of the form of - ax2+bx+c represents a quadratic function. The…

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A: Topic =Parabola

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A: Take the derivative of the given function and equate to zero.

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