A reversible liquid-phase reaction, 2 A <-> B, is to be run in one or more adiabatic reactors. The rate law for this reaction is known to be: -rA = k(CA^ 2 – CB/K) Where the rate constant and equilibrium constant are given by: k = 575 exp ( −12000 / RT ) k = 14000 exp [ ∆H / R ( 1 / To − 1 / T )] k [=] cm^3 / mol. min where T is in K, and the enthalpy of reaction, ΔHRx, is given below. a) What is the maximum conversion you could expect to get from this reaction in a single adiabatic reactor? information: CAo = 0.2 mol/cm3, CBo = 0, CSo = 2 mol/cm3 (inlet concentration of the solvent) Mean heat capacities can be used: CpA = 15 J/mol/K, CpS = 20 J/mol/K (heat capacity of the solvent), ΔHRxn(298 K) = -45,000 J/mol, ΔCp = 0, FAo = 1.5 mol/min To = 305 k
A reversible liquid-phase reaction, 2 A <-> B, is to be run in one or more adiabatic reactors. The rate law for this reaction is known to be: -rA = k(CA^ 2 – CB/K) Where the rate constant and equilibrium constant are given by: k = 575 exp ( −12000 / RT ) k = 14000 exp [ ∆H / R ( 1 / To − 1 / T )] k [=] cm^3 / mol. min where T is in K, and the enthalpy of reaction, ΔHRx, is given below. a) What is the maximum conversion you could expect to get from this reaction in a single adiabatic reactor? information: CAo = 0.2 mol/cm3, CBo = 0, CSo = 2 mol/cm3 (inlet concentration of the solvent) Mean heat capacities can be used: CpA = 15 J/mol/K, CpS = 20 J/mol/K (heat capacity of the solvent), ΔHRxn(298 K) = -45,000 J/mol, ΔCp = 0, FAo = 1.5 mol/min To = 305 k
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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A reversible liquid-phase reaction, 2 A <-> B, is to be run in one or more adiabatic reactors. The rate law for this reaction is known to be: -rA = k(CA^ 2 – CB/K) Where the rate constant and equilibrium constant are given by:
k = 575 exp ( −12000 / RT )
k = 14000 exp [ ∆H / R ( 1 / To − 1 / T )]
k [=] cm^3 / mol. min where T is in K, and the enthalpy of reaction, ΔHRx, is given below.
a) What is the maximum conversion you could expect to get from this reaction in a single adiabatic reactor?
information:
CAo = 0.2 mol/cm3, CBo = 0, CSo = 2 mol/cm3 (inlet concentration of the solvent) Mean heat capacities can be used: CpA = 15 J/mol/K, CpS = 20 J/mol/K (heat capacity of the solvent), ΔHRxn(298 K) = -45,000 J/mol, ΔCp = 0, FAo = 1.5 mol/min To = 305 k
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