A rock is thrown vertically upward with a speed of 17.0 m/s from the roof of a building that is 70.0 m above the ground. Assume free fall. A) In how many seconds after being thrown does the rock strike the ground? B) What is the speed of the rock just before it strikes the ground?

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Asked Sep 10, 2019
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A rock is thrown vertically upward with a speed of 17.0 m/s from the roof of a building that is 70.0 m above the ground. Assume free fall. A) In how many seconds after being thrown does the rock strike the ground? B) What is the speed of the rock just before it strikes the ground?

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Expert Answer

Step 1

Given that the initial speed of the stone is 17.0m/s, and distance travelled by the stone is 70.0m.

Write the kinematic equation, and substitute -17.0m/s for u, and 70m for s in the below equation.

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sis the distance travelled by the stone gis the acceleration due to gravity 1 s ut gt 2 tis the time taken by the stone to reach ground uis the initial velocity 1 70m (-17m/s)+98m/s')f 4.9t2 -17t 70 0 -(-17) (17)-4(4.9)(-70) t = 2x4.9 17 40.75 2 x 4.9 t 5.89s or 2.423s t-2.423 sis practically impossible thus t = 5.89s

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Step 2

Write the kinematic equation and substitute 17.0m/s for u...

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vis the final speed of the stone uis the initial speed of the stone 2u22as a is the acceleration of the stone sis the distan ce travelled by the stone V = {u* +2as -17m/s)+2(9.8m/s )(70 m) = 40.75m/s

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