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A rock is tossed straight up with a speed of 26 m/s . When it returns, it falls into a hole 12 mdeep. How long is the rock in the air, from the instant it is released until it hits the bottom of the hole?

Question

A rock is tossed straight up with a speed of 26 m/s . When it returns, it falls into a hole 12 mdeep. How long is the rock in the air, from the instant it is released until it hits the bottom of the hole?

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Step 1

Write the kinematic relation between initial and final velocity

12gh+u
y=
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12gh+u y=

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Step 2

Substituting the values

2(-9.8 m/s2)(-12 m)+(26 m/s)
=30.18 m/s
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2(-9.8 m/s2)(-12 m)+(26 m/s) =30.18 m/s

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Step 3

Since the rock is travelling downwards, the final velocity is negativ...

uat
v-u
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uat v-u

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Science

Physics

Kinematics

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