Question

Asked Jan 13, 2020

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A rock thrown vertically upward from the surface of the moon at a velocity of 24 m/ sec (about 86 km/h) reaches a height of s = 24t - 0.8t2 m in t sec.

a. Find the rock’s velocity and acceleration at time t. (The acceleration in this case is the acceleration of gravity on the moon.)

b. How long does it take the rock to reach its highest point?

c. How high does the rock go? d. How long does it take the rock to reach half its maximum height? e. How long is the rock aloft?

Step 1

Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and specify the other subparts (up to 3) you’d like answered.

Step 2

A rock thrown vertically upward from the surface of the moon at a velocity of 24 m/ sec reaches a height of s= 24t- 0.8t^{2} meters in t seconds.

Find the following parts.

a). The velocity and acceleration of rock at time t.

b). The time takes the rock to reach its highest point.

c). the height of the rock.

Step 3

**Given information:**

Height function is s= 24t...

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