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Asked Dec 5, 2019
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A rocket is launched off the surface of earth. If it has a speed of 2.62×103 m/s, what height above the surface will it reach? Take the radius of the earth to be 6.37×106 m and the mass of the earth to be 5.98×1024 kg.

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Expert Answer

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Consider the mass of the Earth be M, the rocket’s mass be m, the distance of the rocket, that is the height above the Earth’s surface be h, the initial speed of the rocket be ...

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M = 5.98×104 kg v, = 2.62 x10° m/s R = 6.37×10° m

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