A S19 3.4"Х S19 3.4. Cengage| M Inbox (112)-|MindTap × I+ttps:// ng.cengage.com/static/nb/ui/evo/index.html?e ISBN #9781 305 65757 1 &id-4309342 66&snapshot id-1 065250&INDTAPQ search this coursestions2NO(g) +02(g) 2NO2(g)It is observed that, when the concentration of O2 is reduced to 1/4 of its initial value, the rate of the reaction is also reduced to 1/4 of its initial value, When theconcentration of NO is multiplied by 6.13, the rate of the reaction increases by a factor of 37.6.(a) Write the rate expression for this reaction, and give the units of the rate constant k, assuming concentration is expressed as mol L and time is in secondsrate =k units-(b) If INO] were multiplied by 4.91 and [O2] by 2.56, what change in the rate would be observed?The rate would increase by a factor ofNextAutosaved at 9:31 AMBack9:31 Alv2/28/201

Rate law: An expression relating the rate of a reaction to the rate constant and concentrations of…

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Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter5: Signals And Noise

Section: Chapter Questions

Problem 5.7QAP

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The resolution product of Ag2SO3 is 1.5 x 10-14. Calculate E0 for Ag2SO3 (k) + 2e- ↔ 2 Ag (k) + SO32-. Ag + + e- ↔ Ag E0 = + 0.799 V A. + 0.799 VB. + 0.803 VC. + 0.020 VD. + 0.390 V
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Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any â€œdriftâ€ of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…
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Good day I have asked this question already this question is from the lesson about refractometry and I belive that its about linear regression which I don't know how to get the missing value. 28-31. A calibration curve was created, and the results has beenestablished and showed in the table, Assume the following data, Supply the missing value. n 1.55 1.65 1.70 1.80 ??? 1.62 Conc. 10% 15% 25% 35% 22% ??? 28-29.a. 1.66 c. 1.70b. 1.68 d. 1.72 30-31.a. 14.24 c. 16.24b. 15.24 d.17.24
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