A sample of 0.1355g of an unknown monoprotic acid was dissolved in 25.0mL of water and titrated with 0.0950M NaOH. The acid required 19.3mL of base to reach the equivalence point. What is the molar mass of the acid?

Want to see the full answer?
Check out a sample Q&A here


Related Chemistry Q&A
Find answers to questions asked by students like you.
Q: A 50.0mL volume of 0.15 M HBr is titrated with 0.25 M KOH. Calculate the pH after the addition of…
A: HBr and KOH react in a 1:1 ratio. This means 1 mole of HBr reacts with 1 mole of NaOH. `
Q: A 24.0 mL sample of 0.113 MM sulfurous acid (H2SO3) is titrated with 0.1013 M KOH. At what added…
A: Click to see the answer
Q: A 0.1375 M solution of KOH is used to titrate 35.00 mL of 0.257 M HBr. ( Assume that volumes are…
A: We have to predict the balance net ionic equation, species present at equilibrium, volume for…
Q: A 30.0 mL sample of 0.165 M propanoic acid (Ka = 1.3x10^-5) is titrated with 0.300 M KOH. Calculate…
A: Click to see the answer
Q: in an experiment, the molecular formula for calcium hydroxide was determined to be Ca(OH)2. In this…
A: Given that : The mass of Ca = 0.050 g The volume of DI water = 150 mL The molarity of HCl = 0.30 M
Q: A 60.00 mL sample of 0.075 M benzoic acid was titrated using 0.050 M KOH. What will the pH be at the…
A: The information about the H+ ions (hydrogen ions) is derived by the calculation of any certain…
Q: A buffer is prepared by adding 2.50g of lithium fluoride to 125 mL of 0.648M hydrofluoric acid. You…
A: Buffer Solution It is a mixture of weak acid or base with their corresponding conjugate acid or…
Q: adding
A: Mmol of Acid(HNO2)= M × V(mL) = 0.10 × 50.0 = 5.0 mmol Mmol of NaOH = M × V(mL)…
Q: A 50.00 mL aliquot of 0.0100 M NH3 is titrated with 0.02136 M HCl. What is the pH of the solution at…
A: Click to see the answer
Q: [References] A 4.19 g sample of benzoic acid was dissolved in water to give 42.3 mL of solution.…
A: pH is calculated below
Q: A 50.00 mL aliquot of 0.1000 M NaOH is titrated with 0.1000 M HCI. Calculate the pH of the solution…
A: Click to see the answer
Q: A buffer is prepared by mixing 50.0 mL of 0.200 M NaOHwith 100.0 mL of 0.175 M acetic acid.a. What…
A: A buffer solution is made by adding 50 mL of 0.200M NaOH solution with 100 mL of 0.175M CH3COOH…
Q: A 100mL portion of a 0.05 M solution of Na2CO3 is titrated with a 0.06M solution of HCL. A)What…
A: According to the mole concept, in terms of mass, the amount of substance in moles is equal to the…
Q: A titration of a solution of a diprotic acid H2C3H2O4 with 0.955M NaOH required 33.1mL to reach the…
A: Click to see the answer
Q: A 35.00−mL solution of 0.2500 M HF is titrated with a standardized 0.1805 M solution of NaOH at…
A: The given reaction is an example of weak acid vs strong base titration. Weak acid-HF Strong base-…
Q: A 20.0 mL portion of 0.250 M CH3 NH2 (Kb = 4.4 × 10–4) is titrated with 1.00 M HCl. What is the pH…
A: Click to see the answer
Q: A titration was carried out with sodium hydroxide on a 15.00mL sample of a monoprotic unknown weak…
A: Given data,Volume of monoprotic acid=15.0mLMolarity of NaOH=0.535 MVolume of NaOH=16.78mL
Q: 0.02 M NaOH reagent was standardized using 0.1000 g Potassium hydrogen phthalate (204.22 g/mol) and…
A: Click to see the answer
Q: A 25.0 mL sample of 0.150 M butanoic acid is titrated with a 0.150 M KOH solution. What is the pH at…
A: Click to see the answer
Q: A 0.105 gg sample of a monoprotic acid of unknown molar mass is dissolved in water and titrated with…
A: Click to see the answer
Q: A 100.0-mL buffer solution is 0.100 M in NH3 and 0.125 M in NH4Br. What mass of HCl can this buffer…
A: Click to see the answer
Q: A sample of 0.1687 g of an unknown monoprotic acid was dissolved in 25.0 mL of water and titrated…
A: Titration The titration is a process of carrying out a chemical reaction between two chemicals…
Q: 0.0585g of Na2C2O4 10 mL of distilled water, 2 M H2SO4 were added to adjust the KMnO4 solution…
A: A titration is a technique that uses a known concentration of a solution to calculate the…
Q: A 25.0mL sample of 0.653 M HN3 (ka = 1.9 x10^-5) is titrated with 0.777 M KOH Calculate the pH at…
A: Click to see the answer
Q: Calculate the volume at equivalence point and subsequently the pAg when 35.5 mL of 0.125 M I- is…
A: I-(aq) reacts with Ag+(aq) of the titrant to form AgI(s) precipitate. The balanced chemical…
Q: A 0.5224-g sample of an unknown monoprotic acid was titrated with 0.0998 M NaOH. The equivalence…
A: Click to see the answer
Q: A 50.0 ml sample of 0.200 M HNO2 (weak acid) is titrated with 0.400 M KOH. Calculate the pH after…
A: Neutralization reaction is a type of chemical reaction that occurs between acid and base resulting…
Q: A 20.0 mL sample of 0.115 M sulfurous acid (H2SO3) solution is titrated with 0.1014 M KOH. At what…
A: Given,A 20.0 mL sample of 0.115 M sulfurous acid (H2SO3) solution is titrated with 0.1014 M KOH.
Q: 0.4201 g of a unknown monoprotic acid was dissolved in 25.00 mL of water and titrated with 0.09995 M…
A: Click to see the answer
Q: A volume of 30.0 mLmL of a 0.550 MM HNO3HNO3 solution is titrated with 0.670 MM KOHKOH. Calculate…
A: We have to predict the volume of base required to reach equivalence point
Q: A sample of 0.2140 g of an unknown monoprotic acid was dissolved in 25.0 mL of water and titrated…
A: Given- mass of acid = 0.2140 g Volume of acid solution = 25.0 mL Molarity of NaOH solution = 0.0950…
Q: A 10.0 mL aliquot of a 0.200 mol/L HCl solution was titrated with 0.100 mol/L NaOH. what is the pH…
A: Click to see the answer
Q: 75.0 mL of 0.225 M HNO2 is titrated to its equivalence point with 1.00 M NaOH. What is the pH at…
A: Click to see the answer
Q: A 25.0 mL sample of a saturated Ca(OH)2 solution is titrated with 0.030 M HClHCl , and the…
A: This question is based on law of equivalent . ie; M1V1=M2V2 if diacidic then multiply by 2.
Q: A 25.00 mL sample of propionic acid HC3H5O2, of unknown concentration was titrated with 0.141 M KOH.…
A: The balanced chemical equation for the reaction is: From the balanced chemical equation: 1mol. of…
Q: A 10.0 mL aliquot of 0.100 mol/L NaOH solution was titrated with 0.200 mol/L HCl. what is the pH…
A: Click to see the answer
Q: A second titration is performed using the same 0.250 M NaOH in a buret. This time 25.0 mL of anH2SO4…
A: The chemical equation for this reaction is: 2NaOH + H2SO4→ Na2SO4 + 2H2O
Q: 50.0 mL of the 0.50 M LIOH is added to 25.0 mL of 0.40 M H2SO4. What is the pH at this point in the…
A: We have to calculate the pH of solution
Q: Consider the titration of 25.0mL of 0.375MHBr with 0.250MKOH .a.Calculate the volume (in mL) to…
A: HBr and KOH reacts in the following manner:- HBr + KOH → KBr + H2O Thus each mole of HBrreacts…
Q: A 0.2001 g sample of Na2CO3 required 25.10 mL of excess HCl to reach endpoint. The excess HCl was…
A: Click to see the answer
Q: Calculate pF at the equivalence point of a titration of 20.00 mL of 0.01039 M La (NO3)3 with…
A: Here pF can be determined from the Ksp value of LaF3 formed at equivalent point. Data Ksp LaF3 =…
Q: A 100-mL aliquot of a solution containing hydrochloric acid and phosphoric acid is titrated with…
A: Please find the answer attached here with handwritten note.
Q: A 25.0-mL sample of 0.125 M pyridine is titrated with 0.100 MHCl. Calculate the pH at equivalence…
A: Given,Molarity of pyridine = 0.125 M = 0.125 mol/LVolume of pyridine = 25.0 mL = 0.025 L (1 mL =…
Q: A 56.0 mL volume of 0.25 M HBr is titrated with 0.50 M KOH. Calculate the pH after addition of 28.0…
A: When HBr (strong acid) is titrated with KOH (strong base), the H+ ion (from HBr) will react with OH-…
Q: A second titration is performed using the same 0.250 M NaOH in a buret. This time 25.0mL of an H2SO4…
A: The reaction between the strong acid (H2SO4) and strong base (NaOH) is furnished as follows:…
Q: 25.0 mL of 0.200 M HNO2 is titrated to its equivalence point with 1.00 M NaOH. What is the pH at…
A: The equivalence point is the point where the amount of titrant (here NaOH) added is enough to…
Q: A 39.3 mL sample of a 0.313 M aqueous hydrocyanic acid solution is titrated with a 0.202 M aqueous…
A: Click to see the answer











