A sample of 100 information systems managers had an average hourly income of $43.00 with a standard deviation of $7.00. The margin of error is 1.389. Find the 95% confidence interval for the average hourly wage (in $) of all information system managers. O 36 to 50 O 41.611 to 44.389 O 41.838 to 44.162 O 42 to 44

Q: The average salary of 64 employee was 5400 and the sample standard deviation was 280. Find the 90%…

A:

Q: The manager of the local health club is interested in determining the number of times members use…

A: From the given information, number of members n = 15. Average number of visits  Sample standard…

Q: A sample of 16 students was taken from LIU university. These students spent an average of $170 on…

A: from the given data  sample size n= 16 sample mean =170=x sample S.D.=25.50=s confidence level = 98%…

Q: The mean commuting distance of a random sample of 32 American adults was 9.50 miles, with a standard…

A: Given,sample size(n)=32sample mean(x)=9.50standard deviation(s)=6.92degrees of…

Q: The following stemplot shows the swimming speeds, in kilometers per hour (km/h), for a random sample…

A: Solution: a. Let X be the swimming speed of emperor penguins. From the given information,…

Q: The average salary of 36 employee was 4650 and the sample standard deviation was 165. Find the 99%…

A: We associate with the interval estimate is called a confidence interval. This probability indicates…

Q: A random selection of people in a city were asked “How much do you spend on gasoline per  month?”…

A: Obtain the 95% confidence interval that contains the average monthly income for all people in this…

Q: A random sample of 13 hotels in Boston had an average nightly room rate of $172.10 with a sample…

A:

Q: Select all of the following choices that are possible confidence intervals on the population value…

A: The notation r represents the statistic, which is the value of the linear correlation coefficient…

Q: Among various ethnic groups, the standard deviation of heights is known to be approximately three…

A:

Q: Given the data from ten (10) randomly selected European females about their foot length. 22.5  24.7…

A:

Q: In order to estimate the average daily down time. a manufacturer randomly samples 40 days of…

A: From the given information, Sample size n =40 Sample mean, x̅=55.576 Sample standard deviation,…

Q: A random sample of 10 employees of a company was selected to estimate the mean one-way commute time…

A: From the provided information, Sample size (n) = 10 Sample mean (x̅) = 38 Sample standard deviation…

Q: 19) How much money does the average professional football fan spend on food at a single football…

A: It is given that the sample size (n) is 51. The sample mean and standard deviation are 11.00 and…

Q: A college admissions officer takes a simple random sample of 110 entering freshmen and computes…

A: Given,sample size(n)=110sample mean(x¯)=465population standard…

Q: A sample of 64 was taken from a population, with the mean of the sample being 25 and the standard…

A: It is given that  Sample mean = 25 Sample standard deviation = 2 Sample size = 64 Confidence level =…

Q: The average sa!lary of 64 employee was 5400 and the sample standard deviation was 260. Find the 95%…

A: Solution

Q: In the context of the previous question, construct a 95% confidence interval of the mean salary of…

A: Note- Here I giving a solution for the second photo.   Given information- Sample size, n = 40…

Q: A savings and loan association needs information concerning the checking account balances of its…

A: Given datan=14x¯=664.14s=297.29confidence interval is 90%

Q: The average salary of 64 employee was 5400 and the sample standard deviation was 270. Find the 90%…

A:

Q: For a group of 15 men subjected to a stressful situation, the mean number of heartbeats per minute…

A: Sample size (n) = 15Sample mean (x̅) = 126Standard deviations (s) = 4 Significance level (α) = 1-…

Q: At a certain Senior High School, a random sample of 10 male students was taken and found that their…

A: Here, mean is 63.36 and standard deviation is 4.62. We will use one sample t confidence interval.

Q: The daily intakes of milk (in ounces) for ten randomly selected people were: 23.3 28.4 10.5 16.4…

A: Confidence interval: The (1-α) % confidence interval for population standard deviation is given by:

Q: In a sample of 22 people, the average cost of a cup of coffee is $2.83. Assume the population…

A: Given data: Sample size  = 22 Mean = $2.83 standard deviation =  $1.01 Confidence level  = 90% To…

Q: Adult men (20-30 years old) tend to watch sports on television daily. A random sample of 30 young…

A: Hey, since there are multiple subparts posted, we will answer first three subparts. If you want any…

Q: The manager of the local health club is interested in determining the number of times members use…

A: Confidence interval is an interval such that the probability of the true value of an unknown…

Q: What is the 95% confidence interval for the mean number of hours spent by senior high school…

A:

Q: An electrical firm manufactures light bulbs for LCD projectors. A randomly selected sample of 24…

A: We have given that,  Sample mean (x̄) = 600 hours, standard deviation (s) = 50 hours , sample size…

Q: In constructing a 95% confidence interval for the mean, which of the following is the most…

A: Formula : Margin of error: ME=Zα/2 * (σ/√n)

Q: The mean and standard deviation of a random sample of 7 baby orca whales were calculated as 430…

A: Solution: Let X be the weight of all baby orca whales. From the given information, x-bar=430, S=26.9…

Q: A sample of 16 students was taken from LIU university. These students spent an average of $170 on…

A: Given data issample mean(x)=170standard deviation(s)=25.50sample size(n)=16confidence level = 98%

Q: Twenty seven students were randomly selected from a known nornal population and the sample mean was…

A:

Q: It is a simple random sample and it is normal. In the course of designing theater seats, the…

A: The sample mean is obtained below: Thus, the sample mean is 844.375.   The sample standard…

Q: A sample of n = 25 diners at a local restaurant had a mean lunch bill of $16 with a standard…

A: Since we know population standard deviation, use z-distribution to find z-critical value. Find…

Q: For a population, the value of the standard deviation is 2.51. A random sample of 35 observations…

A:

Q: The average salary of 64 employee was 5400 and the sample standard deviation was 260. Find the 90 %…

A:

Q: A random sample of 12 students showed the following time (in hours) of sleep 4.5 5 5.5 6 6 7 7.5 7.5…

A:

Q: A random sample of 10​venture-capital investments in the fiber optics business sector yielded the…

A:

Q: A random sample of small-business managers was given a leadership style questionnaire. The results…

A: It is given that the random sample of score for initiative. The population standard deviation is…

Q: A random sample of 17 hotels in Boston had an average nightly room rate of $165.40 with a sample…

A: It is given that  Sample mean = $165.40 Sample standard deviation = $21.70 Sample size = 17

Q: A random sample of small-business managers was given a leadership style questionnaire. The results…

A: We have to find confidence interval for population mean (μ) Since population standard deviation (σ)…

Q: The Wall Street Journal published a study in May 2019 claiming that it was hard to find CEOS that…

A: One sample t-test: The one -sample t -test is used to determine whether the mean of sample differs…

Q: In a recent study of 42 eighth graders, the mean number of hours per week that they watched…

A: We are required to estimate the interval for the TV watching hours per week from the given sample of…

Q: A study of 4 bolts of carpet showed that their average length was 76.2 yards and the sample standard…

A:

Q: A sample of 64 is taken from a population, with the mean of the sample being 119 and the standard…

A: Option B is correct (113, 125)

Q: A study of a local city is being conducted to find out the average number of people that use public…

A: It is given that confidence level is 0.90, standard deviation is 100 and margin of error E is 11.

Q: In addition to teachers and administrative staff, schools also have many other employees, including…

A: Obtain the 95% confidence interval for the average hourly wage of grounds persons in school…

Q: Consider the following information on years of education:   Mean Standard Deviation N Lower…

A: 1. From the Standard Normal Table, the value of z* for 95% confidence is 1.96. The 95% confidence…

Q: 5. The following data comparing GPAS based on seating position is provided: Position Front of Room…

A: Find the difference between the two means as:x1-x2=3.24-2.97=0.27 Find the  standard deviation as:…

Q: Brian Vanecek, VP of Operations at Portland Trust Bank, is evaluating the service level provided to…

A: From the provided information, Sample size (n) = 64 Sample mean (x̅) = 15 minutes Population…