A sample of 14 small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is normal. The weight of each bag was then recorded. The mean weight was 2 ounces with a standard deviation of 0.12 ounces. The population standard deviation is known to be 0.1 ounce. Which distribution should you use for this problem?Construct a 90% confidence interval for the population average weight of the candies. State the confidence interval.Construct a 98% confidence interval for the population average weight of the candies. State the confidence interval.

Q: Find the value of t a/2 for a 99% confidence interval when the sample size is 30

A: Given Confidence = 99% n=30

Q: To construct a confidence interval for each of the following quantities, say whether it would be…

A: Note: Hey, since multiple subparts are posted, we will answer first three subparts according to our…

Q: Use the given confidence interval to find the population proportion margin of error  0.09<?<0.33

A: Form the given data we have, p^+MOE = 0.33           ......(1)p^-MOE = 0.09           ......(2)

Q: A sample of 200 corporate managers produced the mean job-related stress score of 7.9 with a standard…

A: It is given that,

Q: Given a sample size of 400 with a mean of 80 and the population standard deviation is found to be 35…

A: We have given that,  Sample mean (x̄) = 80, population standard deviation (σ) = 35 and sample size…

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Given Mean=235 s=15.7 n=12

Q: For a confidence level of 80% with a sample size of 24, find the t-score.

A: From the provided information, Confidence level = 80% Level of significance (α) = 1 – 0.80 = 0.20…

Q: Construct the indicated confidence interval for the difference between the two population means.…

A: We have given the amount of time spent watching television by women and by men- For sample 1 for…

Q: In the course of designing theater seats, the sitting heights (in mm) of a simple random sample of…

A: Given information: Total number of adult women(n) is 12. Meanx¯ of height of 12 women is 834 mm.…

Q: A cell phone company claims that the average time a person spends on their phone is 12.8 hours a…

A: Let μ denote the population mean and x¯ denotes the sample mean. Then, μ=12.8 and x¯=12.2. Let n be…

Q: Use the given confidence interval to find the margin of error and the sample mean. (15.3,22.3)

A: We have to find sample mean and margin of error..

Q: . If she wants to make a 95% confidence interval for the mean with the margin of error of 5 cm, at…

A: here from given information , σ = 17 cm MOE = 5cm here Z-critical for 95 % confidence level = 1.96…

Q: find the t/α2 value for a 98% confidence interval for the mean when the sample size is 39.  t/α2=

A: The objective is to find the critical value for 98% confidence interval for the mean.

Q: For a group of 45 students taking a PSDTF test, the mean heart rate was 96 beats per minute, and the…

A:

Q: Use the given confidence interval to find the margin of error and the sample mean . (12.9, 20.1)

A: See the handwritten solution

Q: In a survey, the planning value for the population proportions P* = 0.5. How large a sample should…

A: Given,population proportions (p*)=0.5margin of error (E)=0.04α=1-0.90=0.1α2=0.05Z0.05=1.645  (from…

Q: Use the given confidence interval to find the margin of error and the sample mean.

A:

Q: Use the given confidence interval to find the population proportion margin of error. 0.54<p<0.68

A: Given: 0.54&lt;p&lt;0.68 To find: Margin of error

Q: For a confidence interval of 5.4 +/- 0.2 find the % confidence level if the standard deviation is…

A:

Q: Suppose you would like to conduct a survey to determine the yearly consumption of beef by a typical…

A: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Q: A random sample of 10 employees of a company was selected to estimate the mean one-way commute time…

A: Given Information :  A random sample of 10 employees of a company was selected to estimate the mean…

Q: Construct the indicated confidence interval for the difference between the two population means.…

A: Given:- The data describes the hours men and women had watched television during the previous week.…

Q: Use The t Distribution Table to find the t/α2 value for a 98% confidence interval for the mean when…

A: Given that n = 17 Degrees of freedom = df = n - 1 = 17 - 1 = 16 t/α2 value for a 98% confidence…

Q: Find the length of a 99% confidence interval for the mean of the sample with a standard deviation of…

A: We have given that the 99% confidence interval for the mean of the sample with a standard deviation…

Q: In a random sample of 80 teenagers, the average number of texts handled in a day is 50. The 96%…

A: Given information: n = 80 μ=50 96% confidence interval for the mean number of texts handled by teens…

Q: Select the correct response. a) Given the same sample data, the margin of error in a 90% confidence…

A: a) Given the same sample data, the margin of error in a 90% confidence interval would be smaller…

Q: Given that you have a sample size of 10 different soda pops, with a sample mean of 2.228 and a…

A: Assumptions for using t distribution: The t distribution is used when the sample size is small…

Q: According to NEA Advocate (2007), the averages for the 2005-2006 academic year, 34 CSU Stanislaus…

A: The provided information is x¯1=$65800x¯2=$72400σ1=$12000σ2=$8000n1=34n2=40α=0.05 The critical value…

Q: Use the Student's t distribution to find te for a 0.95 confidence level when the sample is 29. Step…

A: Given that the sample size is 29 and the confidence level is 0.95. That is, c=0.95 and n=29…

Q: For a given sample, a 50% confidence terval for the population mean is narrower than a 90%…

A: For  a given sample size and population standard deviation, the interval estimation of the…

Q: A quality control expert at a pretzel factory took a random sample of 10 bags from a production run…

A:

Q: or a sample of 121 that has a mean of 6540 and a standard deviation of 780, calculate the 90%…

A:

Q: Find the length of a 99% confidence interval for the mean of the sample with a standard deviation of…

A: We have given that the confidence interval 99% for the mean of the sample with a standard deviation…

Q: Find the length of the confidence interval given the following data: s (standard deviation) = 6 n…

A:

Q: Calculate the 95% confidence interval and the 99% confidence interval for a sample of 81 where the…

A: Given : Sample Size, n = 81 Sample Mean, x̄ = 50 sample standard…

Q: An economist is interested in studying the incomes of consumers in a particular country. The…

A: The population standard deviation = $1,000.Z value for 90% confidence interval is 1.645.Sample size…

Q: If the sample mean is 70 and the standard error of the sample mean is 8, what will be the 90%…

A:

Q: Use The t Distribution Table to find the t2 value for a 98% confidence interval for the mean when…

A: Obtain the degrees of freedom.   The degrees of freedom is obtained below as follows:   From the…

Q: The heights of a simple random sample of 400 male high school sophomores in a Midwestern state are…

A: Given info: The heights of a simple random sample of 400 male high school sophomores in a Midwestern…

Q: Identify the t- scores for a 99% confidence interval if the sample size is 70?

A: We have to find critical value.

Q: The cell phone conversations of a random sample of 50 students has a standard deviation of 9.7…

A: Given: n=50σ=9.7CI=90%=0.90

Q: find the t/α2 value for an 80% confidence interval for the mean when the sample size is 14

A:

Q: Assuming that the population is normally distributed, construct a 95% confidence interval for the…

A: Construct the 95% confidence interval for the population mean. The 95% confidence interval for the…

Q: he following stemplot shows the swimming speeds, in kilometers per hour  (km/h), for a random sample…

A: xbar = 9.771 s = 0.944 n = 31

Q: Assuming that the population is normally distributed, construct a 90% confidence interval for the…

A: Solution-: We find 90% confidence interval for the data 1,2,3,4,5,6,7,25 Also, we find confidence…

Q: In a recent study of 42 eighth graders, the mean number of hours per week that they watched…

A: We are required to estimate the interval for the TV watching hours per week from the given sample of…

Q: The average weight of 35 randomly compact automobiles was 2680. The sample standard deviation was…

A: From the provided information, Sample size (n) = 35 Sample mean (x̅) = 2680 Sample standard…

Q: The average weight of 35 randomly selected compact automobiles was 2680 pounds. The sample standard…

A: From the provided information, Sample size (n) = 61 Sample mean (x̅) = 2680 Sample standard…

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Of 293 employees selected randomly from one company, 8.19% of them commute by carpooling.…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.