Question
Asked Nov 26, 2019
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A satellite circles the earth in an orbit whose radius is 1.90 times the earth's radius. The earth's mass is 5.98 x 1024 kg, and its radius is 6.38 x 106 m. What is the period of the satellite?

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Expert Answer

Step 1

Given data:

Let the radius of the satellite, R = 1.90 x (6.38 x 106 ) = 12.122 x 106 m

Mass of the earth, Me = 5.98 x 1024 kg

Step 2

For the satellite:

47T
.(i)
GM
T Time period
R Radius of the sattelite
M Mass of the earth
G = Universal constant =6.673 x1011 N.m2 / kg
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47T .(i) GM T Time period R Radius of the sattelite M Mass of the earth G = Universal constant =6.673 x1011 N.m2 / kg

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Step 3

Plugging in the given valu...

47
T2 R
GM
4x(3.14)
6.673 x10-1 x 5.98 x 1024
=(12.122x 10
1760.4342x 1018+11-24
1760.4342 x 10
T2 176.04342x106
T 176.04342x106
13.268x10
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47 T2 R GM 4x(3.14) 6.673 x10-1 x 5.98 x 1024 =(12.122x 10 1760.4342x 1018+11-24 1760.4342 x 10 T2 176.04342x106 T 176.04342x106 13.268x10

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