A second analyst was attempting to determine the percent KHP in an unknown sample, similar to that in the CEM 262 laboratory experiment 1. The analyst found the molarity of the standardized NaOH solution to be 0.1016 mol/L. Three aliquots of the unknown sample having weights of 0.8181 g, 0.9393 g, and 0.8719 g were titrated with the NaOH solution requiring 20.00 mL, 22.39 mL, and 22.14 mL, respectively. From these data, determine the average percent KHP in the unknown sample.

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Q: In the analysis of a sample for KH2PO4 content, a sample weighing 0.3994 g required 18.28 mL of…

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Q: 6.) 200.0 mL of a 0.435 M Mg(NO3)2 solution was mixed 300.0 mL of 0.715 M NaOH solution. This…

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Q: concentration

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Q: What volume (mL) of 0.0.214 M (NH4)2HPO4 is necessary to precipitate the calcium as Ca3(PO4)2 from…

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Q: If 110.0 mL of 0.0030 MNa2SO4(aq) is saturated with CaSO4, how many grams of CaSO4 would be present…

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Q: not exist in water. For example: Na2O(s) + H2O → 2 NaOH(aq) 6. All salts containing PO43-, CO32-,…

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Precipitation Titration

Precipitation analysis is used to analyze drugs, and to measure the salt content in food and beverages. It is an important concept from the examination point of view many practical questions are asked on the topic. This topic is significant in the professional exams for both undergraduate and graduate courses, especially for