A shear force of S, = 35 kN is applied a distance of a/2 to the left of the vertical mid-line, as shown in the diagram above. The shear modulus of the material G = 35 GPa for all parts. For the main analysis, your tasks are to: a) Find the shear flow distribution around the section b) From this, find the rate of twist

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter8: Applications Of Plane Stress (pressure Vessels, Beams, And Combined Loadings)
Section: Chapter Questions
Problem 8.2.12P: Solve the preceding problem if the diameter is 480 mm, the pressure is 20 MPa, the yield stress in...
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A shear force of S, = 35 kN is applied a distance of a/2 to the left of the vertical mid-line, as shown
in the diagram above.
The shear modulus of the material G = 35 GPa for all parts.
For the main analysis, your tasks are to:
a) Find the shear flow distribution around the section
b) From this, find the rate of twist
Transcribed Image Text:A shear force of S, = 35 kN is applied a distance of a/2 to the left of the vertical mid-line, as shown in the diagram above. The shear modulus of the material G = 35 GPa for all parts. For the main analysis, your tasks are to: a) Find the shear flow distribution around the section b) From this, find the rate of twist
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