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A ship leaves Port A and travels 59 miles due west to point C. It then adjusts its course 39° northward. It travels 85 miles in that direction until it reaches Port B. What angle 0 with respect to due north could the ship have used to travel directly from Port A to Port B? See the figure below. Port B 85 miles 39° 59 miles Port A Carry your intermediate computations to at least four decimal places. Round your answer to the nearest tenth of a degree.

A ship leaves Port A and travels 59 miles due west to point C. It then adjusts its course 39° northward. It travels 85 miles in that direction until it reaches Port B. What angle 0 with respect to due north could the ship have used to travel directly from Port A to Port B? See the figure below. Port B 85 miles 39° 59 miles Port A Carry your intermediate computations to at least four decimal places. Round your answer to the nearest tenth of a degree.

Trigonometry (MindTap Course List)
Trigonometry (MindTap Course List)
8th Edition
ISBN:9781305652224
Author:Charles P. McKeague, Mark D. Turner
Publisher:Charles P. McKeague, Mark D. Turner
Chapter7: Triangles
Section7.1: The Law Of Sines
Problem 36PS
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A ship leaves Port A and travels 59 miles due west to point C. It then adjusts its course 39° northward. It travels 85 miles in that direction until it reaches Port B. What angle 0 with respect to due north could the ship have used to travel directly from Port A to Port B? See the figure below. Port B 85 miles 39° 59 miles Port A Carry your intermediate computations to at least four decimal places. Round your answer to the nearest tenth of a degree.
Transcribed Image Text:A ship leaves Port A and travels 59 miles due west to point C. It then adjusts its course 39° northward. It travels 85 miles in that direction until it reaches Port B. What angle 0 with respect to due north could the ship have used to travel directly from Port A to Port B? See the figure below. Port B 85 miles 39° 59 miles Port A Carry your intermediate computations to at least four decimal places. Round your answer to the nearest tenth of a degree.
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